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WITCHER [35]
4 years ago
6

-300g de acido comercial se disuelve en agua destilada contenidos en un cono, cuyo radio es de 0.005Km y 300cm de altura, si la

densidades de 1.2g/m3 ¿Cuál es la concentración expresada en %m/m?
Chemistry
1 answer:
Bond [772]4 years ago
8 0

Answer:

\%m/m=76.1\%

Explanation:

¡Hola!

En este caso, considerando la información dada, entendemos que se haría primero necesario calcular el volumen del cono en metros cúbicos, teniendo en cuenta que 0.005 km son 5 m y 300 cm son 3 m:

V=\frac{1}{3} \pi r^2h\\\\V=\frac{1}{3} \pi *(5m)^2(3m)=78.5m^3\\\\

Ahora, convertimos esta cantidad a gramos por medio de la densidad para conocer la masa de la solución:

m_{sol}=78.5m^3*\frac{1.2g}{1m^3} =94.2g

Finalmente, aplicamos la definición de %m/m para obtener:

\%m/m=\frac{300g}{300g+94.2g}*100\%\\\\ \%m/m=76.1\%

¡Saludos!

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