A balloon containing 0. 500 mol Ar at 0. 00°C and 65. 0 kPa pressure is expanded by adding more argon. Formula: PV = nRT (R = 8.

Question

AnnZ [28]

2 years ago

10

A balloon containing 0. 500 mol Ar at 0. 00°C and 65. 0 kPa pressure is expanded by adding more argon. Formula: PV = nRT (R = 8.

317 L•kPa/mol•K) What is the original volume of the gas? L.

Mathematics

1 answer:

Nuetrik [128] · Answer 1 · 2022-12-10T00:06:25+03:00

Using an ideal gas equation to solve the problem. Then the original volume is 17.67 liters.

<h3>What is an ideal gas equation?</h3>

An ideal gas is a theoretical composed of a set of randomly moving gas particles that interact only through elastic collision.

Given

A balloon containing 0.500 mol at 0. 00°C and 65.0 kPa pressure are expanded by adding more argon.

Pressure (P) = 65 kPa

Mole (n) = 0.5 mol

Temperature (T) = 0 °C = 273.15 K

Universal gas constant (R) = 8.317 L.kPa/mol.K

We know the ideal gas equation

$\rm PV =nRT\\\\V \ \ = \dfrac{nRT}{P}$

Put the values, we have

$\rm V = \dfrac{0.5*8.317*273.15}{65}\\\\V = 17.67$

Thus, the original volume is 17.67 liters.

More about the ideal gas equation link is given below.

brainly.com/question/4147359