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ludmilkaskok [199]
3 years ago
12

If you want to calculate a z score for a test where your raw score was 24, what other information must you know

Mathematics
2 answers:
Musya8 [376]3 years ago
6 0

Answer:

eight. What does Z score measure? Well, the Z score is the value you get when you standardize with mean at center deviation. So the Z score is supposed to represent the number of standard deviations value as from the mean.

Step-by-step explanation:

Sophie [7]3 years ago
3 0

Answer:

mean and standard deviation

Step-by-step explanation:

Im pretty sure im right

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17 pounds equals 7711.07 grams a day
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30% of the vehicles in a used car lot are trucks. 10% of the vehicles are green. 3% of the vehicles are green trucks. What is th
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The answer would be A.) 0.1
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Sample Work Help Needed! Please answer these questions and show the steps used to solve them. NO DECIMAL ANSWERS (except on thre
anygoal [31]

1. Using the exponent rule (a^b)·(a^c) = a^(b+c) ...

\left(-2x^3y^4\right)\left(5x^9y^{-2}\right)=(-2)(5)\left(x^{(3+9)}y^{(4-2)}\right)\\\\=-10x^{12}y^{2}

Simplify. Write in Scientific Notation

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8 \left(32\times 10^{11}\right)=(8)(32)\times 10^{11}=256\times 10^{11}=2.56\times 10^{13}

3. The distributive property is useful for this.

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... = 15x² +12x – 5x –4

... = 15x² +7x -4

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3 years ago
Combine likes terms to create an equivalent expression 1/7 - 3(3/7h -2/7)
Anastasy [175]

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7}) = \frac{7-9h}{7}

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})

We have to combine the like terms

From given expression,

\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})

By distributive property,

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

a(b + c) = ab + bc

Therefore,

Solve for brackets using distributive property

\frac{1}{7} - (3 \times \frac{3}{7}h) + (3 \times \frac{2}{7})\\\\\frac{1}{7} - \frac{9h}{7} + \frac{6}{7}

Add 1/7 and 6/7

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Thus the equivalent expression is found

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The answer to the question

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