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3 years ago

Do the following set of points describe a function, a relation, both or neither?

Mathematics

1 answer:

harkovskaia [24]3 years ago

4 0

Answer:

It's Both

Step-by-step explanation:

for the first two co-ordinates, there are many y-value for a single x-value, then for the last two co-ordinates theres a single y-value for one x-value

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3.2x20 show work please

Alexeev081 [22]

20 x 3.2 = 64.0

It is equal to 64 because of you do long multiplication, it is 32 x 20 then add back in the decimal point in between the 4 and 0 for the answer.

6 0

4 years ago

Answer asap? my phones about to die!

mylen [45]

Answer:

Step-by-step explanation:

4+13=17

hope this helps :3

if it did pls mark brainliest

3 0

3 years ago

Read 2 more answers

Marisol is painting on a piece of canvas that has and area of 180 square inches. The length of the painting is 1 1/4 times the w

Ivahew [28]

Formula for the rectangle area is a * b, In this case we know that:

a * b = 180
a (width) = unknown
b (length) = 1 1/4a

We can write it down as:

a * 1 1/4 * a = 180
a² * 1 1/4 = 180 / ÷ 1 1/4 (both sides)
a² = 144 / square root (both sides)
a = 12

Doublecheck:

a = 12
b = 1 1/4 * 12 = 15
a * b = 12 * 15 = 180 (so it's correct)

Answer: The dimensions of the painting are <u>12 x 15 inches</u>.

8 0

3 years ago

Please help meeeeee please

Grace [21]

I’m pretty sure it’s SAS

6 0

3 years ago

Find sin(2x), cos(2x), and tan(2x) from the given information.

larisa86 [58]

Since $\cot(x)=\frac{2}{3}$ and $\cot^{2} x+1=\csc^{2} x$ , we know that:

$\left(\frac{2}{3} \right)^{2}+1=\csc^{2} x\\\\\frac{13}{9}=\csc^{2} x\\\\\csc x=\frac{\sqrt{13}}{3}$

If $\csc x=\frac{\sqrt{13}}{3}$ , this means that $\sin x=\frac{3}{\sqrt{13}}$ and by the Pythagorean identity,

$\sin^{2} x+\cos^{2} x=1\\\left(\frac{3}{\sqrt{13}} \right)^{2}+\cos^{2} x=1\\\frac{9}{13}+\cos^{2} x=1\\\cos^{2} x=\frac{4}13}\\\cos x=\frac{2}{\sqrt{13}}$

Using the double angle formula for sine, $\sin(2x)=2\left(\frac{3}{\sqrt{13}} \right)\left(\frac{2}{\sqrt{13}} \right)=\boxed{\frac{12}{13}}$
Using the double angle formula for cosine, $\cos(2x)=1-2\left(\frac{3}{\sqrt{13}} \right)^{2}=\boxed{-\frac{5}{13}}$
So, since tan=sin/cos, $\tan (2x)=\frac{\sin(2x)}{\cos(2x)}=\frac{\frac{12}{13}}{-\frac{5}{13}}=\boxed{-\frac{12}{5}}$

7 0

2 years ago