Question

Find the 29th term 29,33,37,41 (arithmetic)

Answer 1

Answer:

a₂₉ = 141

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 29 and d = a₂ - a₁ = 33 - 29 = 4 , then

a₂₉ = 29 + (28 × 4) = 29 + 112 = 141

Answer 2

Answer:

The 29th term of arithmetic sequence is 141.

Step-by-step explanation:

Here's the required formula to find the arithmetic sequence :

$\longrightarrow{\pmb{\sf{a_n = a_1 + (n - 1)d}}}$

• $\pink\star$ aₙ = nᵗʰ term in the sequence
• $\pink\star$ a₁ = first term in sequence
• $\pink\star$ n = number of terms
• $\pink\star$ d = common difference

Substituting all the given values in the formula to find the 29th term of arithmetic sequence :

• $\purple\star$ aₙ = a₂₉
• $\purple\star$ a₁ = 29
• $\purple\star$ n = 29
• $\purple\star$ d = 4

$\leadsto{\sf{ \: \: a_n = a_1 + (n - 1)d}}$

$\leadsto{\sf{ \: \: a_{29} = 29 + (29 - 1)4}}$

$\leadsto{\sf{ \: \: a_{29} = 29 + (28)4}}$

$\leadsto{\sf{ \: \: a_{29} = 29 + 28 \times 4}}$

$\leadsto{\sf{ \: \: a_{29} = 29 + 112}}$

$\leadsto{\sf{ \: \: a_{29} = 141}}$

$\star \: \: \red{\underline{\boxed{\sf{a_{29} = 141}}}}$

Hence, the 29th term of arithmetic sequence is 141.

$\rule{300}{2.5}$