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kow [346]
3 years ago
12

64, 66, 41, 18, 81Mean:Mode:Median:Range:​

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0
<h3>Answer:</h3>

mean: 54

<h3></h3><h3></h3><h3>Step-by-step explanation:</h3>

mean: add all the numbers then divide by the amount of numbers that are there

270/5= 54

Charra [1.4K]3 years ago
3 0

Answer:

Mean=54

Mode=No mode

Median=64

Range= 63

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Carlos y pedro cumplen el mismo dia. Carlos tiene el doble de edad que pedro cuando pedro tenia la edad que tiene carlos ahora.
earnstyle [38]
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5 0
3 years ago
Select all equations that have infinitely many solutions.
Wewaii [24]

Answer: 4x-8x, t-8=t hope this helps!

Step-by-step explanation:

3 0
3 years ago
In a study of the effect of cooling rate on the hardness of welded joints, 50 welds cooled at a rate of 10°C/s had an average Ro
Studentka2010 [4]

Answer:

a) The 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

b) No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =91.1 represent the sample mean 1

\bar X_2 =90.7 represent the sample mean 2

n1=50 represent the sample 1 size  

n2=40 represent the sample 2 size  

s_1 =6.55 sample standard deviation for sample 1

s_2 =4.32 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Part a

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =91.1-90.7=0.4

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n_1 +n_2 -1=50+40-2=88  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,88)".And we see that t_{\alpha/2}=1.987  

The standard error is given by the following formula:

SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=1.325

Now we have everything in order to replace into formula (1):  

0.4-1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=-1.887  

0.4+1.987\sqrt{\frac{6.55^2}{50}+\frac{4.32^2}{40}}=2.687  

So on this case the 95% confidence interval would be given by -1.887 \leq \mu_1 -\mu_2 \leq 2.687  

Part b

No contradict the result obtained since the confidence interval contains the value 0, so we don't have enough evidence to conclude that we have a significant effect in the colling rate and the hardness.

3 0
3 years ago
I need help with question 3. Part a and b
nadya68 [22]
(a)well, a is 8 / 2,000, which is 1 /250. that means for every 250 bowls, one is chipped
(b)from there, you figure out what times 250 will get you to 10,000. in our case, its 40.
4 0
4 years ago
Read 2 more answers
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Yanka [14]

Answer:why didn’t you want me to scroll down ?  Can you answer my question


Step-by-step explanation:


5 0
3 years ago
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