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maksim [4K]
2 years ago
11

CAN SOMEONE PLEASEEE HELP ME!

Chemistry
1 answer:
Alisiya [41]2 years ago
7 0

Answer:

1) c

2) e

3) cd

4) de

5) ef

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A ball is equipped with a speedometer and launched straight upward. The speedometer reading four seconds after launch is shown a
Andrew [12]

Answer:

Question 1: <u>1 s after the motion starts</u>

Question 2: <u>0 (just when the motion starts)</u>

Explanation:

You will need to work with approximates values because the precision of the speedometers is low and you are requested to find approximate times.

<u>1. From the speedometer shown at the right.</u>

You can obtain how long the ball has been falling from the highest altitute it reached using the speed of 10 m/s shown by the speedometer at the right.

  • Free fall equation: Vf = Vo - gt

  • Vo = 0 ⇒ Vf = gt ⇒ t = Vf / g

For this problem, I recommend to work with a rough estimate of g: g = 10 m/s² ( I will tell you why soon)/

  • t = [10 m/s] / [10 m/s²] = 1 s

That is the time falling. Since four seconds after launch have elapsed, the upward time was 3 seconds. This will let you to calculate the launching speed.

<u>2. Time when the speedometer displays a reading of 20 m/s</u>

First, calculate the launching speed:

  • Vf = Vo - gt

Since the ball was 3 seconds going upward and the speed at the maximum altitude is 0 you get:

  • 0 = Vo - gt

   

  • Vo = gt = 10 m/s² × 3 s = 30 m/s

Now, use the initial velocity to calculate when the ball is going upward with the speedometer reading is 20 m/s

  • 20 m/s = 30 m/s - 10 m/s² × t

  • t = [ 30 m/s - 20 m/s] / [10 m/s²] = 1 s

Thus, the first answer is t = 1 s.

<u />

<u>3. Time when the speedometer displays a reading of 30 m/s</u>

This is the same speec estimated for the launching: 30 m/s.

So, this reading corresponds to the moment when the ball was launched.

Thus time is 0, i.e. it is the same instant of the launch.

If you had worked with g = 9.80 m/s², the time had been negative. This is due to the precision of the instruments.

That is why I recommended to work with g = 10 m/s².

6 0
3 years ago
Select the correct answer.
matrenka [14]

Answer:

At equilibrium the rate of the forward reaction is equal to the rate of the backward reaction.

When the product of a reaction at equilibrium is increased the equilibrium will shift left or to the reactant side. As a result the excess product will get converted to reactant. This is in accordance to Le Chatelier's principle.

Le Chatelier's principle states that when a system is subjected to stress the equilibrium will shift in a direction to minimize effect of the stress.

Thus the products added to the system at equilibrium will make the equilibrium shift to the reactant side, the rate of the reverse or backward reaction will increase.

Explanation:

Hope This Helps Amigo!

5 0
4 years ago
Two reasons that a plant from a rain forest would not survive in a desert home?
ss7ja [257]

Answer: A planet from a rain forest would not survive in a desert home, for the fact they depend on water and as these live from water, without it, this leads to dehydration and with loss of water with plants, nothing is able to survive when it comes to a rain forest plant being in a desert home. Another reason is the high trees and leaves that are providing the plants enough sunlight or shade to grow, it guarantees to help keep the temperature normal. Being in a deserted area would mean that there would be a temperature change, something the plant is not used to. Without that needed shade and avoiding the scorching sun, they will die out from how different the temperature is, and how hot it is.

Explanation: I hope this helped you.

4 0
3 years ago
Read 2 more answers
Convert a density of 7.2 g/ml into the unit kg/L
aivan3 [116]

Unit conversion is a multi-step process, in which division or multiplication by a numeral factor is involved.

Density = 7.2 g/mL    (given)

Since, 1 g = 0.001 kg and

1 mL = 0.001 L

Now, converting 7.2 g/mL to kg/L:

7.2 \frac{g}{mL}\times \frac{1 kg}{1000 g}\times \frac{1000 mL}{1 L}

= 7.2 kg/L.

Hence, density is 7.2 kg/L.

6 0
3 years ago
When two fluorine atoms bond together in F2, what type of covalent bond do they form?
makvit [3.9K]

When two  fluorine  atoms  bond  together  in f2  the  type of covalent  bond   do they  form is non-polar covalent   bond.


  Explanation

They are  two type of covalent bond.  that is non polar covalent bond and  polar covalent  bond.


Non polar  covalent  bond  is formed  when atoms share  a pair  of electrons  with each other  equally.

polar covalent  bond is bond formed when  atoms share  a pair   electrons unequally.


 F2  is a non polar  since  it is made  up of two  same atoms   which  has  the  same electronegativity, therefore equal number of electrons exist  in the  orbital overlap.


4 0
3 years ago
Read 2 more answers
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