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balu736 [363]
3 years ago
10

QUICK PLEASE HELP!!!during a combustion reaction, 5.00 grams of oxygen reacted with 5.00 grams of CH4.

Chemistry
1 answer:
stealth61 [152]3 years ago
6 0
The balanced chemical reaction is:

CH4 + 2O2 —> CO2 + 2H2O

You need to convert mass to moles (divide by molar mass):

CH4 moles = 5 / 16 = 0.31 mol
O2 moles = 5 / 32 = 0.16 mol

To figure out which reactant is limiting, divide the actual moles by the corresponding coefficient in the reaction:

CH4: 0.31 / 1 = 0.31
O2: 0.16 / 2 = 0.08

O2 is the lower number, so it is the limiting reactant. From the reaction we know it takes 2 moles of O2 to react with each mole of CH4. Therefore, for however many moles of O2 we actually have, half as many moles of CH4 will react. Since we have 0.16 mol of O2, only 0.08 mol of CH4 will react, leaving behind 0.31 - 0.08 = 0.23 mol of CH4.

Now convert back to mass (multiply by molar mass) to find the mass of CH4 remaining:

0.23 x 16 = 3.68g

The closest answer is B.
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A sample in the laboratory is found to contain 3.36 grams of hydrogen, 20.00 grams of carbon, and 26.64 grams of oxygen. The mol
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Answer:

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Molecular formula = C₆H₁₂O₆

Explanation:

Given data:

Mass of hydrogen = 3.36 g

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Solution:

Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

Number of gram atoms of H = 3.36 / 1.01 = 3.3

Number of gram atoms of O = 26.64 / 16 = 1.7

Number of gram atoms of C = 20 / 12 = 1.7

Atomic ratio:

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           1.7/1.7                :     3.3/1.7       :       1.7/1.7

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Empirical formula is CH₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = CH₂O = 12×1 + 2× + 16

Empirical formula mass = 30

n = 180.156 / 30

n = 6

Molecular formula = n (empirical formula)

Molecular formula = 6 (CH₂O)

Molecular formula = C₆H₁₂O₆

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