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Nadya [2.5K]
3 years ago
13

Pleaze help im gonna fail this semester

Chemistry
2 answers:
Shalnov [3]3 years ago
7 0

when hydrogen peroxide mixed with vinegar makes peracetic which is potentially toxic and irritate skin, eyes and respiratory system.

alexandr1967 [171]3 years ago
3 0
Hydrogen peroxide mixed with vinegar makes peracetic acid, which is a toxic gas that irritates the skin and respiratory system
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Help me out with these three formulas
ddd [48]
Carbon dioxide it should be water oxygen
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An ionic bond occurs between what particles
kakasveta [241]
<span>The correct answer is that an ionic bond forms between charged particles. To form this bond, the particles transfer valence electrons (those in the outermost orbit). Specifically, in ionic bonding, the metal atom loses its electrons (thus becoming positive) and the nonmetal atom gains electrons (thus becoming negative).</span>
4 0
3 years ago
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The red line of the hydrogen emission spectrum has a wavelength of 656.1 nm. Calculate the energy of one photon
Effectus [21]

The formula we can use here is the Plancks equation:

E = h c / ʎ

where h is Plancks constant = 6.626 × 10-34 m2 kg / s, c is speed of light = 3 x 10^8 m/s and ʎ is wavelength = 656.1 x 10^-9 m

 

Therefore E is:

E = (6.626 × 10-34 m2 kg / s) * (3 x 10^8 m/s) / 656.1 x 10^-9 m

<span>E = 3.03 x 10^-19 J</span>

4 0
3 years ago
Which statement describes an atomic nucleus?
likoan [24]
The nucleus consists of the protons and neutrons. It contains the most mass in the atom. 
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3 years ago
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Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of
lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

U_{2}-U_{1}=Q-W

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

dw=Pdv

The pressure is constant, so:  w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg} (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

U_{2}-U_{1}=500-(3*75)=275kJ

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

P_{1}V_{1}=nRT_{1}

P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}  

Subtracting the first from the second:

1.5P_{1}V_{1}=nR(T_{2}-T_{1})

Isolating T_{2}:

T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}

Assuming that it is water steam, n=0.1666 kmol

V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}

T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76 ºC

7 0
3 years ago
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