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2 years ago

FeO , or iron (II) oxide , has what ratio of iron to oxygen atoms?

Chemistry

1 answer:

kifflom [539]2 years ago

7 0

Answer:

This is a ratio of two small integers, 1.500 = 3:2. Let's assume that in the molecule of ferrous oxide there is one oxygen atom and one iron atom, and the ratio of the mass of the oxygen atom to the mass of the iron atom is 0.2865.

Explanation:

Molecular weight of Iron (II) oxide= FeO Molecular weight of Iron (III) oxide= Fe2O3

In FeO , every one iron atom contains one oxygen atom.

In Fe2O3, every one iron atom contains 1.5 oxygen atoms.

So FeO(II) will contain more Iron than FeO(III).

Calculation of percentage of iron is not necessary. I think this argument

alone is enough to prove this.

However on calculating the % of Fe, in FeO and Fe2O3 we get,

% of Iron in FeO= 55.85/(55.85+16) =55.85/71.85= 77.73%

% of Iron in Fe2O3= (2 x55.85)/(111.7+48)

=111.7/159.48 = 69.94%

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Which equation represents a spontaneous transmutation?ca(s) + 2h2o(ℓ) → ca(oh)2(aq) + h2(g)2kclo3(s) → 2kcl(s) + 3o2(g)?

stepladder [879]

Correct Answer: Ca(s) + 2H2O(ℓ) → Ca(OH)2(aq) + H2(g)

Reason:
A reaction (transmutation) is said to be spontaneous if it occurs on it's own, without any external stimulus. For spontaneous reaction, change in free energy (ΔG) is negative.

Among the given reactions, Ca(s) + 2H2O(ℓ) → Ca(OH)2(aq) + H2(g) occurs on its own with supplying external energy. Hence, it is a spontaneous reaction. Further, it is an exothermic reaction. So during the reaction heat is given out by the system.

On other hand, reaction: 2KClO3(s) → 2KCl(s) + 3O2(g) is a decompostion reaction. For occurrence of reaction, heat has to be supplied to system. Hence, this reaction is non-spontaneous in nature.

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3 years ago

What mass, in grams, of CO2 and H20 N is formed from 2.55 mol of propane?

Black_prince [1.1K]

Answer: The mass of $CO_2$ and $H_2O$ produced are 336.6 g and 183.6 g respectively.

Explanation:

The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.

Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.

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a) 1 mol of propane produces = 3 moles of $CO_2$

Thus 2.55 mol of propane produces = $\frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2$

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b) 1 mol of propane produces = 4 moles of $H_2O$

Thus 2.55 mol of propane produces = $\frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O$

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The mass of $CO_2$ and $H_2O$ produced are 336.6 g and 183.6 g respectively.

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3 years ago

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