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4 years ago

Convert the following75 mL to L

Chemistry

1 answer:

Marizza181 [45]4 years ago

7 0

Answer:

0.075 L

Explanation:

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Using the image below, describe in at least 2 paragraphs, what is happening with the arrows. Name and explain the processes and

Eddi Din [679]

Answer: I'm sorry, but we can't see the image from NASA

Explanation:

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3 years ago

what would the percentage of thorium-232 ( parent compound) be in a rock that was dated at 1.8 billion years

vovikov84 [41]

The half-life of Th-232 is 1.405 × 10¹⁰ years

Time elapsed = 2.8 x 10⁹ years

Equation of radioactive decay:

A = A₀ = (1/2)^ t/t₁/₂

Thus, the percentage of thorium-232 in the rock that was dated at 2.8 billions year = 87.1%

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4 years ago

I NEED HELP PLEASE, THANKS! :)

TEA [102]

Answer:

$K=\frac{[CaO][CH_{4}][H_{2}O ]^{2} }{[CaCO_{2}][H_{2}]^4 }$

Explanation:

The equilibrium expression is the K value equal to the product of the concentrations of the products over the product of the concentrations of the reactants. If there is a coefficient in front of the compound, raise the molecule to that power.

Since K is big, more product is expected. This is because of mathematic principles. A large numerator with a small denominator will produce a large number.

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3 years ago

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A reaction that is NOT thermodynamically favored at low temperatures can become thermodynamically favored at high temperatures

Rom4ik [11]

Explanation:

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3 years ago

Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of

Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

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4 years ago