Answer:
so the reaction rate increases by a factor 6.
Explanation:
For the given equation the reaction is first order with respect to both ester and sodium hydroxide
So we can say that the rate law is
![Rate(initial)=K[NaOH][CH_{3}COOC_{2}H_{5}]](https://tex.z-dn.net/?f=Rate%28initial%29%3DK%5BNaOH%5D%5BCH_%7B3%7DCOOC_%7B2%7DH_%7B5%7D%5D)
now as per given conditions the concentration of ester is increased by half it means that the new concentration is 1.5 times of old concentration
The concentration of NaOH is quadrupled means the new concentration is 4 times of old concentration.
The new rate law is
![Rate(final)=K[1.5XNaOH][4XCH_{3}COOC_{2}H_{5}]](https://tex.z-dn.net/?f=Rate%28final%29%3DK%5B1.5XNaOH%5D%5B4XCH_%7B3%7DCOOC_%7B2%7DH_%7B5%7D%5D)
the final rate = 6 X initial rate
so the reaction rate increases by a factor 6.
More collisions occur making the particles used up
Answer:
Element Helium have<u> 2 energy levels. </u>
Explanation:
<u>HELIUM -</u> With the symbol He and the atomic number 2, helium is a chemical element. It is a colorless , odorless, tasteless, non-toxic, inert, monatomic gas that is the first in the periodic table in the noble gas group. Of all the elements, its boiling point is the lowest.
At about 24 % of the total elemental mass, which is more than 12 times the mass of all the heavier elements combined, it is present. In both the Sun and Jupiter, its abundance is identical to this. This is due to helium-4's very high nuclear binding energy (per nucleon) with respect to the next three elements following helium.
<u>Hence , the answer is 2 energy levels in Helium atom.</u>
<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.
<u>Explanation:</u>
All radioactive decay processes undergoes first order reaction.
To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:
![k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%20%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken = 1.52 hrs
= Initial concentration of reactant = 100 g
[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g
Putting values in above equation, we get:

To calculate the half life period of first order reaction, we use the equation:

where,
= half life period of first order reaction = ?
k = rate constant = 
Putting values in above equation, we get:

Hence, the half life of the sample of silver-112 is 3.303 hours.
I believe the correct answer would be the first option. It is 100 mL graduated cylinder that is the best apparatus that could be used. It has the smallest graduation as compared to the other choices. It can measure up to 0.1 mL.