A part of the periodic table is shown below.
1 answer:
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1) Chemical equation
<span>4C3H5(NO3)3(l) 12CO2(g) + 6N2(g) + 10H2O(g) + O2(g)
2) Molar ratios
4 mol C3H5(NO3)3 : 10 mol H2O
3) Convert grams of water into number of moles:
numer of moles = mass in grams / molar mass = 120 g / 18.0158 g/mol =
number of moles = 6.66 moles H2O.
4) use proportion and solve for x
4 mol C3H5(NO3)3 / 10 mol H2O = x / 6.66 mol H2O
=> x = 6.66 mol H2O * 4 mol C3H5(NO3)3 / 10 mol H2O = 2.66 mol C3H5(NO3)3
5) Convert </span><span>2.66 mol C3H5(NO3)3 into grams
mass in grams = molar mass * number of moles = 227.0995 g * 2.66 mol = 605.07 g
Answer: 605.07 g
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<span>4C3H5(NO3)3(l) 12CO2(g) + 6N2(g) + 10H2O(g) + O2(g)
2) Molar ratios
4 mol C3H5(NO3)3 : 10 mol H2O
3) Convert grams of water into number of moles:
numer of moles = mass in grams / molar mass = 120 g / 18.0158 g/mol =
number of moles = 6.66 moles H2O.
4) use proportion and solve for x
4 mol C3H5(NO3)3 / 10 mol H2O = x / 6.66 mol H2O
=> x = 6.66 mol H2O * 4 mol C3H5(NO3)3 / 10 mol H2O = 2.66 mol C3H5(NO3)3
5) Convert </span><span>2.66 mol C3H5(NO3)3 into grams
mass in grams = molar mass * number of moles = 227.0995 g * 2.66 mol = 605.07 g
Answer: 605.07 g
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