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Verizon [17]
3 years ago
14

If an electron fell to a lower orbit or energy level, energy would be

Chemistry
2 answers:
Artyom0805 [142]3 years ago
6 0
After an electron has moved to an inner orbital from an outer orbital, it releases energy in the form of light.
arsen [322]3 years ago
5 0
It would emit energy in most of the cases in form of light
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PLEASE HELP ITS VERY EASY FOR OTHER PLEASE ITS A TEST DUE IN AN HOUR PLEASEEEEEEEEEE
STatiana [176]

Answer:

I think it is three times I'm not sure

5 0
3 years ago
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Put hydrogen bonds dispersion forces and dipole-dipole forces in order
Sergeu [11.5K]
Increasing order of strength needed to break bonds:
temporary dipole induced dipole interactions
Permanent dipole induced dipole interactions
Hydrogen bonding
3 0
3 years ago
If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced
Fed [463]

Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂  +  17O₂  →   14CO₂  +  12H₂O

moles of C₆H₁₄O₂  = mass × molar mass

moles of C₆H₁₄O₂ =  16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

                 O₂      :     CO₂

                 17       :      14

                499     :      14/17× 499 = 410.9 moles

          C₆H₁₄O₂   :   CO₂

                    2    :      14

                 1947 :     14/2× 1947 =  13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

5 0
3 years ago
Read 2 more answers
A scuba diver that ascends to the surface too quickly can experience decompression sickness, which occurs when nitrogen that dis
Butoxors [25]

Answer:

The factor that will change the volume of the diver's lungs upon reaching the surface is 4

Explanation:

Given data:

Pressure increases 1 atm = 101.325 kPa

34 ft = 10.3632 m

Depth of 102 ft = 31.0896 m

Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?

The pressure at 31.0896 m:

P_{1} =101.325+(\frac{31.0896}{10.3632} *101.325)=405.3kPa

The factor will the volume of the diver's lungs change upon arrival at the surface:

\frac{V_{2}}{V_{1} } =\frac{P_{1}}{P_{2}} =\frac{405.3}{101.325} =4

5 0
3 years ago
Identify each of the following half-reactions as either an oxidation half-reaction or a reduction half-reaction.
koban [17]

Answer:

Cu+(aq)--->Cu2+(aq) + e- : oxidation

reason: there is loss of electrons.

I2(s) + 2e--->2I-(aq) : reduction

reason: There is reduction of electrons.

5 0
3 years ago
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