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Archy [21]
3 years ago
9

Determine the oxidation number for nitrogenin

Chemistry
1 answer:
iris [78.8K]3 years ago
7 0

Answer:

1(a) N = 3

(b) N = 0

(c) N = 5

(d) N = -2

(2) Molecular formula for benzene is C6H6

Explanation:

1(a) N02 1-

N + (2×-2) = -1

N-4 = -1

N = -1+4 = 3

(b) N2

2(N) = 0

N = 0/2 = 0

(c) NO2Cl

N + ( 2×-2) + (-1) = 0

N - 4 - 1 = 0

N - 5 = 0

N = 0+5 = 5

(d) N2H4

2(N) + (4×1) = 0

2N + 4 = 0

2N = 0 - 4 = -4

N = -4/2 = -2

(2) Molcular mass of benzene = 78g/mole = (6×12g of carbon) + (6×1g of hydrogen) = 72+6 = 78g/mole

Therefore, molecular formula for benzene is C6H6

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What type of chemical reaction is given by the following balanced equation: 2C8H18 + 25O2 → 16CO2 + 18H2O
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Answer:

Explanation:

           2C₈H₁₈ + 25O₂    →  16CO₂   +  18H₂O

The reaction above is a typical combustion reaction which are very common with hydrocarbons. Combustion occurs in the presence of oxygen to product carbon dioxide and water. The purpose of this reaction is to transform chemical energy into useful heat energy. Most times, the oxygen used is always in excess of the hydrocarbon reacting with it.

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Liquid alcohol will change to vapor when its temperature reaches the
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Describe how surface ocean currents would be affected if earth did not rotate
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Which an element that exist into two form​
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Sulphur

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3 0
3 years ago
A new compound was recently discovered and found to have an atomic weight of 342.38 amu. This element has two isotopes, the ligh
Rufina [12.5K]

Answer:

The mass of heavier isotope is 345.6 amu.

Explanation:

Given data:

atomic wight of compound = 342.38 amu

lighter isotope mass = 340.91 amu

abundance of lighter isotope = 68.322%

mass of heavier isotope = ?

Solution:

average atomic mass = ( % age abundance of lighter isotope × its atomic mass) + (% age abundance of heavier isotope × its atomic mass)  / 100

percentage of heavier isotope = 100- 68.322 = 31.678

Now we will put the values in formula.

342.38  = (68.322× 340.91) + (31.678 × X) / 100

342.38 = 23291.65302 +  (31.678 × X) / 100

342.38 × 100 = 23291.65302 +  (31.678 × X)

34238 -23291.65302 =  (31.678 × X)

10946.35 / 31.678 = X

345.6 = X

The mass of heavier isotope is 345.6 amu.

5 0
3 years ago
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