Answer:
D. -1882J
Explanation:
We can solve the energy released in a chemical reaction in an aqueous medium using the equation:
Q = -m*C*ΔT
<em>Where Q is energy (In J),</em>
<em>m is mass of water (45.00g)</em>
<em>C is specific heat of water (4.184J/g°C)</em>
<em>And ΔT is change in temperature (25.00°C - 15.00°C = 10.00°C)</em>
<em />
Replacing:
Q = -45.00*4.184J/g°C*10.00°C
Q = -1882J
Right answer is:
<h3>D. -1882J</h3>
<em />
The radon-222 sample has a half-life of 3.8 days, and we are asked how many times would the mass divide in half after 23 days. First we calculate the amount of times division occurs by taking the number of days and dividing that by the number of days for one half-life to occur: 23/3.8 = 6.05.
We have 198.6 grams of sample, and we are going to divide it in half 6 times to determine how much of it remains after 23 days:
198.6/2 = 99.3 grams
99.3/2 = 49.65 grams
49.65/2 = 24.83 grams
24.83/2 = 12.41 grams
12.41/2 = 6.21 grams
6.21/2 = 3.1 grams
Therefore, we are left with 3.1 grams of radon-222 after 23 days if one half-life equals to 3.8 days.
Answer:
3,3-Dimethyloct-4-yne · Contents · 1Structures · 2Names and Identifiers · 3Chemical and Physical Properties · 4Related Records · 5 Patents · 6 ..
This is not chemistry but
see it is a triangular prim on it's side
V=BH
are of base times height
the base is a triangle
height is 18.5
base=1/2bh
b=8.6
h=8.4
base=1/2(8.6)(8.4)
base=36.12
V=bh
V=36.12*18.5
V=668.22
round
V=668.2 ft^3
