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OleMash [197]
3 years ago
10

An atom of cadmium that has 66 neutrons has a mass number of

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
7 0

Answer:

113

Explanation:

We are given that the atom of cadmium has 66 neutrons:

  Number of neutrons in Cd  = 66

Now;

 Mass number  = ?

The mass number of an element is the sum of the number of protons and number of neutrons

     Mass number  = number of protons + number of neutrons

 By the position of cadmium, it has an atomic number of 47 and this is the number of protons

     Mass number  = 47 + 66  = 113

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BaCl2(aq) + Na2CO3(aq) BaCO3(s) + NaCl(aq
Vitek1552 [10]
This is the equation balanced:

<span>BaCl2(aq) + Na2CO3(aq) = BaCO3(s) + 2 NaCl(aq)

Then the coefficient in front of Na Cl is 2.

Answer: 2
</span>


7 0
4 years ago
What are some pros and cons of endoskeletons and exoskeletons
xenn [34]
Endoskeleton
Pros: bones do not get broken so easily
If bones broken, can heal more quick since they are inside with good blood and nutrient supply

Cons: flesh can easily get damage
no shedding of endoskeletons, so no new skeleton cannot if injuried.

Change those up for exoskeletons.. pros for cons and cons for pros
3 0
3 years ago
Read 2 more answers
A chemist adds of a M calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist h
Levart [38]

Answer:

1.23 g

Explanation:

<em>A chemist adds 1.55 L of a 0.00582 M calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask.</em>

Step 1: Given data

  • Volume of the solution (V): 1.55 L
  • Molar concentration of the solution (C): 0.00582 M (0.00582 mol/L)

Step 2: Calculate the moles (n) of calcium sulfate added

We will use the following expression.

n = C × V

n = 0.00582 mol/L × 1.55 L

n = 0.00902 mol

Step 3: Calculate the mass corresponding to 0.00902 moles of calcium sulfate

The molar mass of calcium sulfate is 136.14 g/mol.

0.00902 mol × 136.14 g/mol = 1.23 g

6 0
3 years ago
Sulfuric acid is produced in larger amounts by weight than any other chemical. It is used in manufacturing fertilizers, oil refi
Fed [463]

Answer:

A. -166.6 kJ/mol

B. -127.7 kJ/mol

C. -133.9 kJ/mol

Explanation:

Let's consider the oxidation of sulfur dioxide.

2 SO₂(g) + O₂(g) → 2 SO₃(g)     ΔG° = -141.8 kJ

The Gibbs free energy (ΔG) can be calculated using the following expression:

ΔG = ΔG° + R.T.lnQ

where,

ΔG° is the standard Gibbs free energy

R is the ideal gas constant

T is the absolute temperature (25 + 273.15 = 298.15 K)

Q is the reaction quotient

The molar concentration of each gas ([]) can be calculated from its pressure (P) using the following expression:

[]=\frac{P}{R.T}

<em>Calculate ΔG at 25°C given the following sets of partial pressures.</em>

<em>Part A  130atm SO₂, 130atm O₂, 2.0atm SO₃. Express your answer using four significant figures.</em>

[SO_{2}]=[O_{2}]=\frac{130atm}{(0.08206atm.L/mol.K).298K} =5.32M

[SO_{3}]=\frac{2.0atm}{(0.08206atm.L/mol.K).298K} =0.0818M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0818^{2} }{5.32^{3} } =4.44 \times 10^{-5}

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln (4.44 × 10⁻⁵) = -166.6 kJ/mol

<em>Part B  5.0atm SO₂, 3.0atm O₂, 30atm SO₃  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=\frac{5.0atm}{(0.08206atm.L/mol.K).298K}=0.204M

[O_{2}]=\frac{3.0atm}{(0.08206atm.L/mol.K).298K}=0.123M

[SO_{3}]=\frac{30atm}{(0.08206atm.L/mol.K).298K}=1.23M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{1.23^{2} }{0.204^{2}.0.123 } =296

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 296 = -127.7 kJ/mol

<em>Part C Each reactant and product at a partial pressure of 1.0 atm.  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=[O_{2}]=[SO_{3}]=\frac{1.0atm}{(0.08206atm.L/mol.K).298K}=0.0409M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0409^{2} }{0.0409^{3}} =24.4

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 24.4 = -133.9 kJ/mol

7 0
3 years ago
Question 1 of 10
Natalka [10]

Answer:

C

Explanation:

A- incorrect, not in alphabetical order

B- incorrect, symbol for salt in NA not SA

C- correct

D- incorrect, not based on discovery

5 0
4 years ago
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