Answer:
a) heat it from 23.0 to 78.3
q = (50.0 g) (55.3 °C) (2.46 J/g·°C) =
b) boil it at 78.3
(39.3 kJ/mol) (50.0 g / 46.0684 g/mol) =
c) sum up the answers from the two calculations above. Be sure to change the J from the first calc into kJ
Explanation:
Answer:
The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the remaining electron in the 3s. Therefore the sodium electron configuration will be 1s22s22p63s1.
Explanation:
Answer:
A.) trans-2,3-dichloro-5-methyl-2-hexene
Explanation:
The proposed question and structure has been attached to this answer.
The<em> cis</em>- and <em>trans</em>- isomers are used to denote the alignment of the functional groups to the carbon chain side. From the diagram, we see that:
- the two chloro groups on the main compound are in opposite directions (-<em>trans</em>), and not the same sides (-<em>cis</em>)
- The bottom extended methyl group is on the 5th carbon as we count from left to right
- there's a total of 6 carbon atoms with 1 double bond on the second to third carbon.
Hence the name <u>trans-2,3-dichloro-5-methyl-2-hexene</u>
Answer:
evaporation or distillation
Answer:
II and IV.
Explanation:
To know which option is correct, do the following:
Energy (E) and frequency (f) are related by the following equation:
E = hf
Where:
E is the energy.
h is the Planck's constant.
f is the frequency.
From the equation E = hf
Energy is directly proportional to the frequency. This implies that an increase in the frequency will also increase the energy and a decrease in the frequency will also decrease the energy.
Therefore, (II) in the question above is correct.
Velocity (v), wavelength (λ) and frequency (f) are related by the following equation:
v = λf
Divide both side by λ
f = v/λ
Thus, we can see clearly that the frequency is inversely proportional to the wavelength. This means that an increase in frequency will decrease the wavelength and a decrease in frequency will increase the wavelength.
Therefore, (IV) in question above is correct.
Thus, II and IV are the correct answers.
