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Ann [662]
3 years ago
5

What is the meaning of acid?​

Chemistry
2 answers:
weqwewe [10]3 years ago
7 0

Answer:

a substance which when dissolved with water makes H+ ions

Dimas [21]3 years ago
3 0
A chemical substance that neutralizes alkalis, dissolves some metals, and turns litmus red; typically, a corrosive or sour-tasting liquid of this kind.
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What are these smooth, distinct layers most directly evidence of ?
Neko [114]

Answer: The layers of the rocks in one region of the parks are smooth and distinct, which are evidence of many, many years of deposition. The layers on the rocks are because of different deposition of sediments. Different sediments deposited over the rocks through wind, water and ice over the ages

Explanation:

5 0
3 years ago
Read 2 more answers
Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i
vaieri [72.5K]

Answer:

The value is x  =  0.151  \ e

Explanation:

From the question we are told that

The bond length is l  =  1.93\  \r  a =  1.93 *1 *10^{-10}  =1.93 *10^{-10}\  m

The bond dipole moment is \mu  = 1.40 d  = 1.40 *  3.33564 *10^{-30}  =  4.6699 *10^{-30} \  C \cdot m

Generally the dipole moment is mathematically represented as

\mu  =  Q *  l

Here Q is the partial negative charge on the bromine atom

So

Q =  \frac{\mu}{ l}

=> Q =  \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }

=> Q = 2.42 *10^{-20} C

Generally

1 electronic charge(e) is equivalent to 1.60*10^{-19} C

So x electronic charge(e) is equivalent to Q = 2.42 *10^{-20} C

=> x  =  \frac{2.42 *10^{-20}}{1.60*10^{-19} }

=>     x  =  0.151  \ e

3 0
3 years ago
Which describes the molecule shown below?
lana [24]

Answer:

Option D. Saturated alkane

Explanation:

To know which option is correct, it is important that we know what saturated and unsaturated compounds are in this context.

Saturated hydrocarbons are compounds which has only carbon to carbon single bonds (C–C) in its chain. A very good example of such compound is the Alkanes.

Unsaturated hydrocarbons are compounds which has either a carbon to carbon double bond (C=C) or a carbon to carbon triple bond (C≡C) in its chain. Examples of such compounds include alkenes and alkynes.

Now, let us answer the question given above bearing the meaning of saturated and unsaturated compounds in mind.

The compound given above contains only carbon to carbon (C–C) single bond.

Therefore, the compound is a saturated alkane.

5 0
3 years ago
Use the following equation to answer the questions and please show all work.
DIA [1.3K]

Answer:

a.36 g of water is produced.

b.64 g of O_{2} is consumed.

Explanation:

The reaction is 2H_{2} + O_{2}⇒2H_{2}O

a.

Given,

Weight of H_{2} reacted = 4g

Weight of 1 mole of H_{2} = 2\times1 = 2g

Therefore no. of moles of H_{2} reacted = \frac{4}{2} = 2 moles;

Also given,

Weight of O_{2} reacted = 32 g

Weight of 1 mole of O_{2} = 2\times16 = 32 g

Therefore no. of moles of O_{2} reacted = \frac{32}{32} = 1

We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,

As we took 2 moles of Hydrogen and 1 mole of Oxygen,

Directly,from the equation we can tell 2moles of water will be produced.

Therefore no. of moles of H_{2} O produced = 2

Weight of 1 mole of water = 2\times 1+16 = 18

Therefore weight of H_{2}O produced = 2\times 18 = 36gm

b.

Given ,

72 g of H_{2}O is produced.

So,

no. of moles of H_{2}O produced =\frac{72}{18} = 4 moles

From equation For every 2 moles of water formed , 1 mole of oxygen must be required.

So for producing 4 moles of water,

No. of moles of Oxygen required = 2 moles.

Therefore weight of O_{2} reacted = 2\times32 = 64 g

Method 2:

Given,

8 g of H_{2} has reacted.

So,

no. of moles of H_{2} reacted = \frac{8}{2} = 4 moles.

From equation , we know that For every 2 moles of H_{2} reacted,1 mole of O_{2} will react.

Therefore,

No. of moles of O_{2} that reacts with 4 moles of H_{2} = 2\times1 = 2 moles

Therefore the weight of O_{2} reacted = 2\times 32 = 64 g

6 0
3 years ago
A saturated solution of barium fluoride, BaF2BaF2, was prepared by dissolving solid BaF2BaF2 in water. The concentration of Ba2+
babunello [35]

Answer: 1.70\times 10^{-6}

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as

The equation for the ionization of the BaF_2 is given as:

BaF_2\rightarrow Ba^{2+}+2F^-

When the solubility of BaF_2 is S moles/liter, then the solubility of Ba^{2+}  will be S moles/liter and solubility of F^- will be 2S moles/liter.

By stoichiometry of the reaction:

1 mole of BaF_2 gives 1 mole of Ba^{2+ and 2 moles of F^-

K_{sp}=[Ba^{2+}][F^{-}]^2

K_{sp}=s\times (2s)^2

K_{sp}=4\times (7.52\times 10^{-3})^3

K_{sp}=1.70\times 10^{-6}

Thus K_{sp} for BaF_2 is 1.70\times 10^{-6}

7 0
4 years ago
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