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3241004551 [841]
2 years ago
11

Help me with this science question on the middle one..

Chemistry
1 answer:
viktelen [127]2 years ago
8 0
Networks of feeding relationships is correct
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If an equilibrium mixture of the three gases at 600K contains 2.92*10^-2 M COCH(g) and 1.76*10^2 M CO, what is the equilibrium
Vlad [161]

Answer:

C

Explanation:

7 0
2 years ago
What's the answer ???
lesya692 [45]
The answer would be step three but not positive this is correct hope this helps
5 0
3 years ago
An FAS calibration curve (absorbance, y-axis vs. FAS in g/mL) gave an equation he regression line of: y-3678(x)+0.056. If an unk
mezya [45]

Answer:

FAS concentration = 1.61*10^-4M

Explanation:

Beer Lambert's law relates the absorbance (A) of a substance to its concentration (c) as:

A = \epsilon lc----(1)

where ε = molar absorption coefficient

l = path length

A plot of 'A' vs 'c' gives a straight line with slope = εl

In addition absorbance (A) is related to % Transmittance (%T) as:

A = 2-log%T----(2)

For the FAS solution, the corresponding calibration fit is given as:

y = 3678(x) + 0.056

This implies that the slope = εl = 3678

It is given that %T = 25.6%

A = 2-log(25.6)=0.592

Based on equation(1):

c = \frac{A}{\epsilon l}=\frac{0.592}{3678}=1.61*10^{-4}M

8 0
2 years ago
Is anyone else's brainly not working or is mine the only one that is tweaking?
omeli [17]
Mine tweaking as well
5 0
3 years ago
Look at picture please
Tom [10]

Answer:

Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.

Explanation:

First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.

Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.

Hence the answer above.

3 0
2 years ago
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