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3241004551 [841]
3 years ago
11

Help me with this science question on the middle one..

Chemistry
1 answer:
viktelen [127]3 years ago
8 0
Networks of feeding relationships is correct
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2 nf3 + 225 kj -> n2 + 3f2 is it exothermic or endothermic
velikii [3]
Due to energy being a reactant instead of a product, the process is endothermic. The system must absorb a quantity of energy before it can react, so it must be an endothermic system.
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4 years ago
Write the balanced chemical equation for the reaction of khp with naoh
liubo4ka [24]

Answer:

KHP + NaOH ⟶ KNaP + H₂O

Explanation:

The H in KHP is the acidic hydrogen. The OH⁻ in NaOH neutralizes it  and converts it to H₂O.

The balanced equation for the reaction is

KHP + NaOH ⟶ KNaP + H₂O

5 0
3 years ago
What are the science definitions of these
Alecsey [184]

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Era

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Overpopulation means to have more tham capacity for a particular area/ habitat.
Tanya [424]

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Hope this helps

4 0
3 years ago
A chemist adds 26.5g of ammonium chloride to 10g of sodium hydroxide, which follows the reaction below. Assuming the reaction go
4vir4ik [10]

Answer :  The amount of reactant left in excess is 13.1075 grams.

Explanation : Given,

Mass of NH_4Cl = 26.5 g

Mass of NaOH = 10 g

Molar mass of NH_4Cl = 53.5 g/mole

Molar mass of NaOH = 40 g/mole

First we have to calculate the moles of NH_4Cl and NaOH.

\text{Moles of }NH_4Cl=\frac{\text{Mass of }NH_4Cl}{\text{Molar mass of }NH_4Cl}=\frac{26.5g}{53.5g/mole}=0.495moles

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{10g}{40g/mole}=0.25moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

NH_4Cl+NaOH\rightarrow NH_4OH+NaCl

From the balanced reaction we conclude that

As, 1 mole of NaOH react with 1 mole of NH_4Cl

So, 0.25 moles of NaOH react with 0.25 moles of NH_4Cl

From this we conclude that, NH_4Cl is an excess reagent because the given moles are greater than the required moles and NaOH is a limiting reagent and it limits the formation of product.

Moles of remaining excess reactant = 0.495 - 0.25 = 0.245 moles

Now we have to calculate the mass of NH_4Cl.

\text{Mass of }NH_4Cl=\text{Moles of }NH_4Cl\times \text{Molar mass of }NH_4Cl

\text{Mass of }NH_4Cl=(0.245mole)\times (53.5g/mole)=13.1075g

Therefore, the amount of reactant left in excess is 13.1075 grams.

5 0
3 years ago
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