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aleksklad [387]
2 years ago
12

Is 1.165 greater than 1.02

Mathematics
2 answers:
avanturin [10]2 years ago
7 0

Answer:

yes

Step-by-step explanation:

if u put  1.02 into the thousandths it becomes 1.020 which is obviously less than 1.165

andreev551 [17]2 years ago
4 0

Answer:

yes

Step-by-step explanation:

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Which shows one way to determine the factors of x3 – 9x2 + 5x – 45 by grouping?
Valentin [98]
Factoring by grouping usually pairs up the first 2 sets of expressions with the second 2 sets.  Ours looks like this, then:  (x^3-9x^2)+(5x-45)=0.  If we factor out the common x-squared in the first set of parenthesis, along with factoring out the common 5 in the second set, we get this:  x^2(x-9)+5(x-9).  Now the common expression that can be factored out is the (x-9).  When we do that, here's what it looks like:  (x-9)(x^2+5).  I'm not sure how far you are going with this.  You could set each of those equal to 0 and solve for x in each case.  The first one is easy.  If x - 9 = 0, then x = 9.  The second one involves the imaginary i since x^2 = -5.  In that case,  x=i \sqrt{5},-i \sqrt{5}.  Hopefully, in what I have given you, you can find what you're looking for.
7 0
3 years ago
20% of a is 11. What is a?
a_sh-v [17]

Answer:

a is 5.

b is 16.

c is 24.

D is 9.

7 0
3 years ago
A TV company when purchasing thousands electronic components apply this sampling plan: randomly select 15 of them and then accep
katrin [286]
<h2>Answer with explanation:</h2>

According to the Binomial probability distribution ,

Let x be the binomial variable .

Then the probability of getting success in x trials , is given by :

P(X=x)=^nC_xp^x(1-p)^{n-x} , where n is the total number of trials or the sample size and p is the probability of getting success in each trial.

As per given , we have

n = 15

Let x be the number of defective components.

Probability of getting defective components = P = 0.03

The whole batch can be accepted if there are at most two defective components. .

The probability that the whole lot is accepted :

P(X\leq 2)=P(x=0)+P(x=1)+P(x=2)\\\\=^{15}C_0(0.03)^0(0.97)^{15}+^{15}C_1(0.03)^1(0.97)^{14}+^{15}C_2(0.03)^2(0.97)^{13}\\\\=(0.97)^{15}+(15)(0.03)^1(0.97)^{14}+\dfrac{15!}{2!13!}(0.03)^2(0.97)^{13}\\\\\approx0.63325+0.29378+0.06360=0.99063

∴The probability that the whole lot is accepted = 0.99063

For sample size n= 2500

Expected value : \mu=np= (2500)(0.03)=75

The expected value = 75

Standard deviation :  \sigma=\sqrt{np(1-p)}=\sqrt{2500(0.03)(0.97)}\approx8.53

The standard deviation = 8.53

6 0
3 years ago
How to solve the polynomial 5x+3y+6x+9y
ANEK [815]

5x+3y+6x+9y

All you'd need to do is combine like terms. So add 5x to 6x and add 3y to 9y.

(5x+6x)+(3y+9y)

Final Answer: 11x + 12y

3 0
3 years ago
Read 2 more answers
17. Mary Palm's checking account had a starting balance of $785.63. She wrote a check for $57.00 for groceries and a check for $
Scrat [10]

Answer:B 660.88

Step-by-step explanation:

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Last add 603.63 to 125.00

To give 660.88

4 0
3 years ago
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