2/5 of the students is equivalent to 394 students. The total number of students involved is thus 394*5/2.
Answer:
The value of the unit rate is 8
Step-by-step explanation:
we know that
To calculate the unit rate simply divide the first number by the second number
so
Convert mixed number to an improper fraction
substitute in the expression above
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
Answers:
13 42 m; B; 0.57 m
Step-by-step explanation:
Data:
Pool A: r = 22 ft
Pool B: D = 13.6 m
Calculations:
1. Radius of Pool A
r = 22 ft × (0.305 m/1 ft) = 6.71 m
2. Diameter of Pool A
D =2r = 2 × 6.71 = 13.42 m
The diameter of Pool A is 13.42 m.
3. Compare pool diameters
The diameter of Pool B is 13.6 m.
So, the diameter of Pool <u>B</u> is greater.
4. Compare circumferences
The formula for the circumference of a circle is
C = 2πr or C = πD
Pool A: C = 2π × 6.71 = 42.16 m
Pool B: r = π × 13.6 = 42.73 m
Pool B - Pool A = 42.73 - 42.16 = <u>0.57 m
</u>
The circumference is greater by <u>0.57 m.</u>
Answer:
Step-by-step explanation:
16-2t=t+9+4t
7=7t
t=1
