Answer:
73.6
61.824
.2776
2.3
1.342
.4129
*note* I had trouble reading the standard deviation of the second part, so if it's not 3 then leave a comment and i will fix it*
Step-by-step explanation:
1.)
the mean would be something like 460*.16= 73.6
The variance should be 460*.16(1-.16)= 61.824 which means the standard deviation is √61.824= 7.863
for p to be less than .15 it would have to be less than .15*460= 69
(69-73.6)/7.863= -.59 which has a probability of .2776
2.)
the mean is 2.3
I am not sure if the standard deviation is 3 or .3 (picture is kind of blurry)
I am thinking that it's three which would mean that the standard deviation would be √(3²*(1/5))= 1.342
(2-2.3)/1.342= -.22 = .4129
Answer:
Step-by-step explanation:
The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:
where:
is the area of the base, where
L is the length of the base
is the area of each triangular face, where
h is the height of the face
Substituting,
For the model in this problem,
L = 12
h = 8
Therefore, the surface area here is:
Answer:
y= -2x-22.
Step-by-step explanation:
1) the slope-interception common form is y=s*x+i, where 's' and 'i' are the slope and interception, unknown numbers;
2) if x₁= -3; y₁= -16, and s=-2, then the equation of the required line can be written in the point-interception form y-y₁=s(x-x₁); ⇔ y+16= -2(x+3);
3) the required equation in slope-interception form is:
y+16= -2x-6; ⇒ y= -2x-22.
note, the provided solution is not the only and shortest way.
Answer:
This cannot be solved unless I have the coordinate for triangle "abc"
Step-by-step explanation:
Once I have the coordinates for triangle "abc", I can solve to find out where triangle "A'B'C" is
