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ss7ja [257]
2 years ago
13

Vita has a piece of ribbon that is 5 meters long. She cuts the ribbon into pieces that are each 1/3 meter long. How many pieces

does she cut?
Mathematics
1 answer:
Zanzabum2 years ago
7 0

Answer:

so this is clearly a division problem

the equation will be

5 ÷1/3     Keep switch flip

according to KSF the equation will change to this

5*3  = 15

So she will be able to cut 15 peices.

Thank you, Hope it helps

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How to solve the problem 3.2d-4d=2.3d+3
Liula [17]
3.2d - 4d = 2.3d + 3...simplify by combining like terms
-0.8d = 2.3d + 3....subtract 2.3d from both sides
-0.8d - 2.3d = 3 ...simplify again
-3.1d = 3...divide both sides by -3.1
d = 3/ -3.1
d = - 0.97

or
3.2d - 4d = 2.3d + 3....multiply the equation by 10, gets rid of the decimals
32d - 40d = 23d + 30....subtract 23d from both sides
32d - 40d - 23d = 30....simplify
-31d = 30...divide by -31
d = -30/31
d = - 0.97
5 0
2 years ago
3 pieces of wood have a total length of 32 m. The second piece is twice the size of the first and the third piece is 2 more mete
andreev551 [17]

Answer:

X + Y + Z = 32

X2 = Y

X3 + 2 = Z

X + X2 + X3 + 2 = 32

Make X alone

There is a 2 so we subtract 2 from both sides

X + X2 + X3 = 30

Add the X's up

X + X2 + X3 = X6

X6 = 30

Divide by 6

30 / 6 = 5

You are left with X=5

The first piece of wood has a length of 5

5 x 2 = 10

The second piece has a value of 10

5 x 3 + 2 = 17

The third piece is 17

Hope this helps. If you have any questions you may ask.

Step-by-step explanation:

5 0
3 years ago
A man keeps birds in a big cage in his garden.
andreev551 [17]
Changchun. eh just h dhchre
7 0
3 years ago
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

4 0
3 years ago
How do you put 20/80 in simplest form
Andrews [41]

GCF = 20

Reduce the fraction by dividing
the numerator and denominator by 20
and get the simplified answer

<span><span>20 ÷ 20=1 || 80 ÷ 20</span>=4 
<em>1/4</em> is your answer! :D</span>
5 0
3 years ago
Read 2 more answers
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