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Vika [28.1K]
3 years ago
8

The problem is in the pic​

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

(3, -1)

Step-by-step explanation:

The vertex is the lowest point of the parabola.  The coordinates for this vertex are: (3, -1).

The first coordinate is the x-coordinate, which is moved to the right by 3.  The second coordinate is the y-coordinate, which is moved down one, or negative 1).

:)

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What's the answer ????
gizmo_the_mogwai [7]
The mistake is line 4, she should have divided 42 by 5, not add 5 and 16
5 0
4 years ago
An art studio charges a start-up fee to cover art supplies, plus an additional fee per class. The graph shows the total cost for
Studentka2010 [4]

Answer/Step-by-step explanation:

✔️The rate of change can be calculated using the coordinates of any two points on the graph. Let's use (2, 60) and (3, 75):

rate of change = \frac{y_2 - y_1}{x_2 - x_1} = \frac{75 - 60}{1} = \frac{15}{1} = 15

Rate of change (m) = 15

✅In the context of this situation, the rate of change can be interpreted to be the additional fee per class. Thus, an additional fee per class cost $15.

✔️Initial value is the same as the y-intercept.

To find the y-intercept (b), substitute m = 15, x = 2, and y = 60 into y = mx + b.

Thus:

60 = 15(2) + b

60 = 30 + b

60 - 30 = b

30 = b

b = 30

The initial value/y-intercept = $30

✅In this context, $30 is the start-up fee to cover art supplies.

5 0
3 years ago
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0
4 years ago
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kotegsom [21]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help please I’ll give you 25 points
Ira Lisetskai [31]

Answer: Choice D) y = \pm \sqrt{x+5}

The steps to finding the inverse will have us swap x and y. Afterward, we solve for y

y = x^2 - 5 \\\\x = y^2 - 5 \\\\x+5 = y^2 \\\\y^2 = x+5 \\\\y = \pm \sqrt{x+5} \\\\

------------------------------

Extra info:

The inverse relation is not a function because of the plus minus. For instance, plugging x = 4 into y = \pm \sqrt{x+5} leads to y = -3 and y = 3 simultaneously. You would have to apply a domain restriction on y = x^2-5 to make it a one-to-one function, to make the inverse a function. One possible domain restriction is x > 0 which would lead to the inverse function y = \sqrt{x+5}

4 0
3 years ago
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