The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.
Given:
- Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a pound
- The resulting mixture should be 50 pounds of candy
- The resulting mixture should cost $1.30 a pound
To find: The amount of candy costing $1.25 a pound that should be mixed
Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.
Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '
' pounds of candy costing $1.45 a pound.
Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '
' pounds of candy costing $1.45 a pound.
Accordingly, the total cost of the resulting mixture is ![1.25x+1.45(50-x)](https://tex.z-dn.net/?f=1.25x%2B1.45%2850-x%29)
However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is ![1.30 \times 50](https://tex.z-dn.net/?f=1.30%20%5Ctimes%2050)
Equating the total cost of the resulting mixture obtained in two ways, we get,
![1.25x+1.45(50-x)=1.30 \times 50](https://tex.z-dn.net/?f=1.25x%2B1.45%2850-x%29%3D1.30%20%5Ctimes%2050)
![1.25x+72.5-1.45x=65](https://tex.z-dn.net/?f=1.25x%2B72.5-1.45x%3D65)
![0.2x=7.5](https://tex.z-dn.net/?f=0.2x%3D7.5)
![x=\frac{7.5}{0.2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B7.5%7D%7B0.2%7D)
![x=37.5](https://tex.z-dn.net/?f=x%3D37.5)
This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.
Learn more about cost of mixtures here:
brainly.com/question/17109505
Answer:
310 Hz
Step-by-step explanation:
This is a spanish language mathematical question.
We translate this to english:
An observer approaches a static speaker at 15 meters per second. The speaker is emitting a sound with a frequency of 297 Hz. What is the frequency perceived by the observer?
<u>Solution:</u>
<u />
This can be solved using doppler effect formula. Which is:
![f=(\frac{c}{c+V_s})f_0](https://tex.z-dn.net/?f=f%3D%28%5Cfrac%7Bc%7D%7Bc%2BV_s%7D%29f_0)
Where
f is the observed frequency (297 Hz)
c is the speed of sound (343 m/s)
is the velocity of source (given as 15)
is what we want to find
Now, substituting, we solve:
![f=(\frac{c}{c+V_s})f_0\\297=(\frac{343}{343+15})f_0\\297=(0.9581)f_0\\f_0=309.99](https://tex.z-dn.net/?f=f%3D%28%5Cfrac%7Bc%7D%7Bc%2BV_s%7D%29f_0%5C%5C297%3D%28%5Cfrac%7B343%7D%7B343%2B15%7D%29f_0%5C%5C297%3D%280.9581%29f_0%5C%5Cf_0%3D309.99)
Rounding,
<u>We can say the perceived frequency would be around 310 Hz</u>
10^9x5.5
So basically it’s like your just adding the zeros at the end except this preference as opposed to seeing all those zeros so scientists chose this method .
Solving an equation like this means to find the value of the variable. Here, the variable is x. Solve the left side normally.
Given: 1/3(9 - 6x) = -11
Distribute: 1/3(9) + 1/3(-6x) = -11
When operating with constant numbers on a variable term, apply affects of the operation on the coefficient. So, 1/3(-6x) = -2x.
3 - 2x = -11
Isolate the variable: 3 - 3 - 2x = -11 - 3
-2x = -14
Since these are both negative, we can convert them both to being positive.
2x = 14
Simplify: 2x/2 = 14/2
<u>x = 7</u>
Answer:
Interphrase
Step-by-step explanation:
Cell replicates its chromosomes and prepares for cell division