Graph a line that is perpendicular to the line y=-3x + 2 and has a y-intercept of -6.
1 answer:
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Step-by-step explanation:
by using y=uv derivative formula and stationary mean y' = 0
y' = 3(x–2)⁴ + 3(3x–1)(x–2)³ = 0
cancel 3 and factorize
(x–2+3x–1)(x–2)³ = 0
x = ¾ or x = 2
we got point and (2,0)
Simple...
you have: 8x-6y=1
You're trying to find m-->>using y=mx+b to re-write the line....
8x-6y=1
8x-6y=1
-8x -8x
-6y=-8x+1
y=
Your slope m=
Thus, your answer.
you have: 8x-6y=1
You're trying to find m-->>using y=mx+b to re-write the line....
8x-6y=1
8x-6y=1
-8x -8x
-6y=-8x+1
y=
Your slope m=
Thus, your answer.
Answer:
I don't know if this helps, just a picture not a link
