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2 years ago

In a right triangle has one leg that measures 11 in and the hypotenuse measures 47 in, what is the length of the other leg?

Mathematics

1 answer:

Wewaii [24]2 years ago

4 0

Using the Pythagorean theorem:

47 ^2 = 11^2 + x^2

2209 = 121 + x^2

Subtract 131 from both sides

2088 = x^2

Take the square root of both sides

X = sqrt(2088)

Simplify

X = 6sqrt(58)

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If u make 120.45 in 15 2/3 hours how long did u work if u made 40.15 ?

Novosadov [1.4K]

Answer:

about 5.22hrs

Step-by-step explanation:

cross multiply

15.67 40.15

120.45*40.15

=629.1505

629.1505/15.67

=5.2233333...

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3 years ago

An equation of the horizontal line that passes through the point (-2,5)

Greeley [361]

Y=5 it's a horizontal lines so b in y=mx+b would have to be 5 and since it's horizonal, it doesn't have a slope so it's just y=5

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3 years ago

Annabel and Riley were given a homework packet of 120 math questions to finish over the summer.

Lena [83]

Step-by-step explanation:

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3 years ago

Order the decimals 0.42, -1/2, 11/20, -0.51

bearhunter [10]

least to greatest: -0.51, -1/2, 0.42, 11/20

greatest to least: 11/20, 0.42, -1/2, -0.51

4 0

3 years ago

A round balloon has a diameter of 7 inches

gizmo_the_mogwai [7]

Answer:

The right answer is approximately 210.031 cubic inches. (Answer: E)

Step-by-step explanation:

First, we need to convert the diameter ( $D$ ), in inches, of the round balloon to an entirely decimal mode:

$D = 7\,in + \frac{3}{8}\,in$

$D = \frac{56 + 3}{8}\,in$

$D = \frac{59}{8}\,in$

$D \approx 7.375\,in$

The volume of the balloon is modelled after the volume function of a sphere ( $V$ ), in cubic inches:

$V = \frac{\pi}{6}\cdot D^{3}$ (1)

If we know that $D \approx 7.375\,in$ , then the volume of the round balloon is:

$V = \frac{\pi}{6}\cdot D^{3}$

$V = \frac{\pi}{6} \cdot (7.375\,in)^{3}$

$V \approx 210.031\,in^{3}$

Hence, the right answer is approximately 210.031 cubic inches.

6 0

3 years ago