In a right triangle has one leg that measures 11 in and the hypotenuse measures 47 in, what is the length of the other leg?
1 answer:
Using the Pythagorean theorem:
47 ^2 = 11^2 + x^2
2209 = 121 + x^2
Subtract 131 from both sides
2088 = x^2
Take the square root of both sides
X = sqrt(2088)
Simplify
X = 6sqrt(58)
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