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4 years ago

Aaron bought a set of plastic ice cubes with a mixture of water and air inside.

Mathematics

1 answer:

LekaFEV [45]4 years ago

6 0

Answer:

Volume of water and air is 3,000 mm³

Step-by-step explanation:

Given:

Length of base = 15 mm

Width of base = 20 mm

Height of figure = 30 mm

Find:

Volume of water and air is inside each of the plastic ice cubes.

Computation:

Height of each rectangular pyramid = Height of figure / 2

Height of each rectangular pyramid = 30 / 2

Height of each rectangular pyramid = 15 mm

Volume of each rectangular pyramid = lbh / 3

Volume of each rectangular pyramid = [15 × 20 × 15] / 3

Volume of each rectangular pyramid = [4,500] / 3

Volume of each rectangular pyramid = 1,500 mm³

Volume of water and air is inside each of the plastic ice cubes = 2 × Volume of each rectangular pyramid

Volume of water and air is inside each of the plastic ice cubes = 2 × 1,500

Volume of water and air is inside each of the plastic ice cubes = 3,000 mm³

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benny had 266 dollars to spend on 9 books. After buying them he had 14 dollars. How much did each book cost?

Anastaziya [24]

Answer:

The books cost $28 dollars each.

Step-by-step explanation:

$266 - $14 = $252

then take $252 divided by 9 = $ 28

7 0

3 years ago

A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%

IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

$P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18$

a) P(firm will make at least one hire)

$P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32$

Also,

$P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4$

$\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9$

b) expected value and the standard deviation of the number of hires.

$E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58$

$E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89$

7 0

3 years ago

Find the perimeter of a polygon with vertices at A(0, 1), B(4, 4), C(7, 0), D(3, -3), E(-4, -4). Round your answer to the neares

wlad13 [49]

It's interesting that areas from coordinates are much simpler than perimeters from coordinates. It's almost like math is telling us area is more fundamental than length.

p = AB+BC+CD+DE+EA

We use the Pythagorean theorem, square root form, on all the sides. We can skip a lot of the square roots because most of these are the hypotenuse of a 3/4/5 right triangle.

B-A=(4-0, 4-1)=(4,3) so length AB=5

C-B=(7-4,0-4)=(3,-4), so again BC=5

D-C=(3-7, -3-0)=(-4,-3) so again CD=5

E-D=(-4-3, -4 - -3) = (-7, -1). Ends our streak. DE=√(7²+1²)=√50=5√2.

A-E=(0 - -4,1 - -4)=(4,5) so EA=√(4²+5²)=√41.

Three of five were 3/4/5.

p = 5+5+5+5√2+√41 = 15+5√2+√41

I hate to ruin a nice exact answer with an approximation.

p ≈ 28.474192049298324

Answer: 28.47, last choice

8 0

3 years ago

Fifteen students were asked which school day was least favorite. How many students chose Monday?

Lynna [10]

The answer would be 3 because you would count the amount of ‘x’s in the chart

4 0

3 years ago

Read 2 more answers

A research study uses 800 men under the age of 55. Suppose that 30% carry a marker on the male chromosome that indicates an incr

ss7ja [257]

Answer:

a) There is a 12.11% probability that exactly 1 man has the marker.

b) There is a 85.07% probability that more than 1 has the marker.

Step-by-step explanation:

There are only two possible outcomes: Either the men has the chromosome, or he hasn't. So we use the binomial probability distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

30% carry a marker on the male chromosome that indicates an increased risk for high blood pressure, so $\pi = 0.30$

(a) If 10 men are selected randomly and tested for the marker, what is the probability that exactly 1 man has the marker?

10 men, so $n = 10$

We want to find P(X = 1). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{10,1}.(0.30)^{1}.(0.7)^{9} = 0.1211$

There is a 12.11% probability that exactly 1 man has the marker.

(b) If 10 men are selected randomly and tested for the marker, what is the probability that more than 1 has the marker?

That is $P(X > 1)$

We have that:

$P(X \leq 1) + P(X > 1) = 1$

$P(X > 1) = 1 - P(X \leq 1)$

We also have that:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{10,0}.(0.30)^{0}.(0.7)^{10} = 0.0282$

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0282 + 0.1211 = 0.1493$

Finally

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.1493 = 0.8507$

There is a 85.07% probability that more than 1 has the marker.

3 0

3 years ago