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fomenos
3 years ago
13

Find the common difference for -31,-26,-21,-16

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

The common differences is 5

Step-by-step explanation:

The difference is 5. Why? Because 5 is added to each term to arrive at the next term. so ... the difference a2 - a1 = 5.

E.g. -31 + 5 = -26

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How Many quarters are in a dollar?
MatroZZZ [7]

Answer:

4 quarters. Each quarter costs 25 cents. 25 x 4=100. There are 100 cents in a 1 dollar, so that's why 4 quarters= 1 dollar.

3 0
3 years ago
Read 2 more answers
An elevator at a department store must carry fewer than 17 people at a time. An elevator operator is present in the elevator at
Anvisha [2.4K]

Answer:

A. x+ 1 < 17

Step-by-step explanation

Customers = x persons

  Operator = 1 person

        Total = x + 1 persons

Total persons must be less than 17.

The inequality is

x + 1 < 17

4 0
3 years ago
How tall is the goal post if its shadow is 18ft. The height of the flagpole is 20 ft and its shadow is 8 ft.?
tamaranim1 [39]

You can set up an inequality to solve this. You can either do big to small --> \frac{x}{18} = \frac{20}{8} or small to big --> \frac{x}{18} = \frac{8}{20}. I'm going to be using big to small because I think it's a little easier.

\frac{20}{8} = \frac{x}{18}

Cross multiply and you will get:

360 = 8x

Isolate x:

x = \frac{360}{8}

x = \frac{90}{2}

x = 45

The goal post is 45 feet tall. Hope this helped. Good luck. : )

6 0
4 years ago
A truck has a force of 2000 newtons and is moving 10 miles per hour. How much mass does the truck have?
worty [1.4K]

Answer:

Force= Mass×Accelaraion

F=m×a

But as The unit of accelaration is given miles per hour and the SI is meters per second sqaure we have to convert 10mph to m/s²

Thus, we have 10mph = 4.47 meters per second square. (i converted using scientific calculator)

So now we have,

2000N= m×4.47m/s²

= 2000/4.47m/s²=m

= 447.42

Thus the mass of the object is 447.42 (i am not sure of units)

7 0
3 years ago
Read 2 more answers
Eight adults and two children need to cross a river. A small boat is available that can hold one adult or one or two children. E
sleet_krkn [62]

Answer:

A = 8, C = 2 => T = 33

A=100, C = 2 => T = 401

A = any, C = 2 => T = 4A + 1

A = 8, C = 4 => T = 37

As long as the boat can carry one adult or one or two children, the following equation should solve the problem.

T = 4A + 2(C-2) + 1

Step-by-step explanation:

To transfer one adult, 4 one-way trips need to be made as follows:

1. Two children cross the river

2. One of them takes the boat back to the other side

3. One adult crosses the river

4. The other child takes the boat back

These four steps are repeated until all adults are crossed. At this point no children has crossed yet.

Then for every 2 children except the last 2, 2 one-way trips need to be made if the number of children is greater than 2:

1. Two children cross

2. One takes the boat back

For the last 2,only one trip needs to be made.

A = number of adults

C = number of children >= 2

T = total trips

T = 4A + 2(C-2) + 1

4 0
3 years ago
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