Answer:
the relationship between fractions, decimals and percents is that they are just different numerical expressions of the same value.
Step-by-step explanation:
For example, 50% =
= 0.50
Answer:
See explanation below.
Step-by-step explanation:
Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.
A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.
Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.
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It might either be a right triangle or a cute triangle
Answer:the answer is
Step-by-step explanation:
First convert 7 1/2 to an improper fraction
15/2 ÷ 3/4
Division of fractions hold the first fraction replaces ÷ with x then flip the second fraction
15/2 x 4/3
Multiply the tops 15x4 =60
Over the bottoms multiplied together 2x3=6
60/6=10
10 people can be served that should help
Answer:
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Step-by-step explanation:
m<MON = 8x - 13°
m<LOM = 7x - 17°
To find : m <MON
First, we have to find the value of x :
Create an equation
( sum of angle in straight line )
Collect like terms

Calculate

Move constant to R.H.S and change its sign

Calculate the sum

Divide both sides of the equation by 15

Calculate

Now, let's find the value of m<MON

Plug the value of x

Calculate the product

Calculate the difference
°
Hope I helped!
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