![\bf tan(39^o)=\cfrac{\stackrel{opposite}{x}}{\stackrel{adjacent}{8}}\implies 8\cdot tan(39^o)=x\implies 6.48\approx x \\\\[-0.35em] ~\dotfill\\\\ \cfrac{sin(39^o)}{x}=\cfrac{sin(51^o)}{8}\implies \cfrac{8\cdot sin(39^o)}{sin(51^o)}=x\implies 6.48\approx x](https://tex.z-dn.net/?f=%5Cbf%20tan%2839%5Eo%29%3D%5Ccfrac%7B%5Cstackrel%7Bopposite%7D%7Bx%7D%7D%7B%5Cstackrel%7Badjacent%7D%7B8%7D%7D%5Cimplies%208%5Ccdot%20tan%2839%5Eo%29%3Dx%5Cimplies%206.48%5Capprox%20x%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7Bsin%2839%5Eo%29%7D%7Bx%7D%3D%5Ccfrac%7Bsin%2851%5Eo%29%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B8%5Ccdot%20sin%2839%5Eo%29%7D%7Bsin%2851%5Eo%29%7D%3Dx%5Cimplies%206.48%5Capprox%20x)
one thing to bear in mind is that calculators have two modes, Degree mode and Radian mode, if your calculator is in Radian mode and you plug in tan(39), it thinks "tangent of 39 radians" and so it gives that, bearing in mind that 1 radian is about 57°.
So make if you're using degrees as the angle, make sure your calculator is in Degree mode first, thus tan(39) will mean "tangent of 39 degrees".
Answer:
The balance in the account increases at a rate of 2.5% each year
Check the picture below.
the triangle has that base and that height, recall that A = 1/2 bh.
now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,
so, add AC + AB + CB, and that's the perimeter of the triangle.
seperable differential equations will have the form
what you do from here is isolate all the y terms on one side and all the X terms on the other
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
so all you need to integrate is
