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Wittaler [7]
2 years ago
12

Can someone plz help me?

Mathematics
2 answers:
Hitman42 [59]2 years ago
6 0

Answer:

B

Step-by-step explanation:

Katena32 [7]2 years ago
4 0
B I think I’m not sure
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It costs James an initial $7 fee to ride a taxi. Plus 6$ a minute. He ends up paying
malfutka [58]

Answer:

$78

Step-by-step explanation:

Can i be brain list

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3 years ago
You have $1,000 to invest. You invest 25% in a Money Market account, 50% in stocks, and 25% in bonds. What is the dollar amount
kirill115 [55]

Answer:

you have $250 in market and bonds and $500 in stocks.

step-by-step explanation:

you split 1,000 into 4 quarter and take two of those quarters and there is what you invested in stocks and take one quarter for market and one quarter for bonds.

7 0
3 years ago
The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y
kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

d(x)=-4x^3+x^2

For finding out the distances for x=1 and x=2

let us substitute 1 and 2 for x

d(1) = -4(1^3)+1^2 = -3

d(2) = -4(2^3)+2^2 \\= -28

d(1) = -3 and d(2)= -28

3 0
3 years ago
The polygons are similar, but not necessarily drawn to scale. Find the scale factor. Find the value of x. Find the value of y.
Tatiana [17]

Answer:

x = 5

y = 9

Step-by-step explanation:

Since the scale is 2, the side of x needs to 4 because the corresponding side on the other figure is 2 (2 * 2 = 4).

So, x - 1 = 4

x = 5

Similar to the y side, the y side needs to be 10.

So, y + 1 = 10

y = 9

3 0
3 years ago
If f(x) = g(x+1) and g(x) = x^2, find the value of f(3).
Elena-2011 [213]

\bf \begin{cases} f(x)=&g(x+1)\\ f(3)=&g(3+1)\\ &g(4)\\[-0.5em] \hrulefill& \hrulefill\\ g(x)=&x^2\\ g(4)=&4^2\\ &16 \end{cases}\qquad \qquad f(3)\implies g(4)\implies 16

8 0
3 years ago
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