We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
V/a = 3/5
a = 20
v = ...
3/5 = v/20
5v = 20*3
5v = 60
v = 60/5
v = 12 oz
Answer:
A
Step-by-step explanation:
Edge 2021
The giving functions are from dofferent types. transforming a function does not change it's type so it is impossible to transfer f(x)=2 to f(x)=(x-3)^2-1.
Scale factor mark brainliest plz