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Ilia_Sergeevich [38]
3 years ago
6

A rectangular solid has sides of 7 cm + 9 cm + 11 cm what is its surface area

Mathematics
2 answers:
alina1380 [7]3 years ago
6 0

Your answer would be: <em>693.</em>

Explanation:

When finding the area in a problem use <em>L×W×H</em>.

That being said, you now have to multiply the <em>L×W×H</em> (7x9x11)

7 × 9 × 11 = <em>693</em>

So the answer would be <em>693</em> because, if you are finding an area you use <em>L×W×H</em> to find your area.


trasher [3.6K]3 years ago
5 0

Answer:

478

Step-by-step explanation:

Surface Area=2(ab+ac+bc)

SA=2((7*9)+(7*11)+(9*11))

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Here is the required diagram .

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Alternate angles are equal .

4 0
3 years ago
In the diagram, what is the value of x? <br><br> A. 144° <br> B. 28° <br> C. 5° <br> D. 36°
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X+4x = 180
5x = 180
x =180/5
x = 36

answer
D. 36
4 0
3 years ago
The difference of a number N and 9 is fewer than 4
denis23 [38]
Any number less than or equal to 12
5 0
3 years ago
A light bulb consumes 960 watt hours per day how long does it take to consume 4320 watt hours
VARVARA [1.3K]

Since we need to determine how long it takes for the watt hours to consume 4320 watt hours, we would need to divide.

We would simply divide.

4320/950= 4.5

The 4.5 represents how long it would take for the light bulb to consume 4320 watt hours.

Therefore, the answer would be 4.5 days.

<u>Answer</u>

4.5 days

<u>Recap</u>

1. We read the problem and determined that in order to solve the problem we would need to divide.

2. We then divided 4320/960= 4.5

3. We came to the conclusion that 4.5 days would be the answer.

7 0
3 years ago
Find the point on the line 2x+4y−3=0 which is closest to the point (2,0)
Finger [1]
L1: 2x+4y-3=0 ..........(1)
P: (2,0)
The point on the line L1 closest to the given point P is at the intersection of L1 with L2, which is the perpendicular passing through P. 

Slope of L1=-2/4=-1/2
Slope of L2=-1/(-1/2)=2
Since it passes throug P(2,0), we can use the point-slope formula:
(y-0)=2(x-2)  =>
L2: 2x-y-4=0.............(2)

Solve for x & y using (1) and (2) to get intersection point required:
(1)-(2)
2x-2x + 4y-(-y) -3 -(-4) =0
5y=-1, y=-1/5
Substitute y=1/5 in equation (1)
2x+4(-1/5)-3=0 =>
2x-19/5=0
x=19/10

=> the point on L1 closest to (2,0) is (19/10, -1/5)

7 0
3 years ago
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