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Fiesta28 [93]
3 years ago
6

Which approach do you think would give your class the best chance at winning explain your reasoning

Mathematics
1 answer:
NARA [144]3 years ago
8 0
Being levelheaded will let you concentrate more on the important things so you can better focus yourself on success
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Please help with 15 i’m desperate please i’ll give u a brainliest
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Find the cost of fencing a rectangular Park of length 150 and breadth 100 at the rate of 20 per metre​
Lyrx [107]

Answer:

Rs 300000

Step-by-step explanation:

Given that,

Length of a rectangular park, l = 150 m

Breadth, b = 100 m

We need to find the cost of fencing the park at the rate of 20 per metre. The area of a rectangle is given by :

A = lb

So,

A=150\times100\\\\A=15000\ m^2

Cost of fencing,

C=15000\times 20\\\\C=Rs\ 300000

So, the required cost is Rs 300000.

6 0
3 years ago
In the equation y=x2 , which of the following explains the unit rate?
muminat
The only logical answer is, 2 because the unit rate is value of y when x=1.

y=(1)2
y=2.

As I stated in the same question, the "Unit Rate" is not hard, it's just slope. They are trying to trick you by saying "unit rate". Your unit rate is x2.
3 0
4 years ago
Find the perimeter of rhombus star
Degger [83]

Answer:

4\sqrt{10}

Step-by-step explanation:

Perimeter of the rhombus, STAR, is the sum of the length of all it's 4 sides.

The coordinates of its vertices are given as,

S(-1, 2)

T(2, 3)

A(3, 0)

R(0, -1)

Length of each side can be calculated using the distance formula given as d = \sqrt{x_2 - x_1)^2 + (y_2 - y_1)^2}

Find the length of each side ST, TA, AR, RS, using the above formula by plugging in the coordinate values (x, y) of each vertices.

ST = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

S(-1, 2) => (x1, y1)

T(2, 3) => (x2, y2)

ST = \sqrt{(2 -(-1))^2 + (3 - 2)^2}

ST = \sqrt{(3)^2 + (1)^2} = \sqrt{9 + 1} = \sqrt{10}

TA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

T(2, 3) => (x1, y1)

A(3, 0) => (x2, y2)

TA = \sqrt{(3 - 2)^2 + (0 - 3)^2}

TA = \sqrt{(1)^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10}

AR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

A(3, 0) => (x1, y1)

R(0, -1) => (x2, y2)

AR = \sqrt{(0 - 3)^2 + (-1 - 0)^2}

AR = \sqrt{(-3)^2 + (-1)^2} = \sqrt{9 + 1} = \sqrt{10}

RS = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

R(0, -1) => (x1, y1)

S(-1, 2) => (x2, y2)

RS = \sqrt{(-1 - 0)^2 + (2 -(-1))^2}

RS = \sqrt{(-1)^2 + (3)^2} = \sqrt{1 + 9} = \sqrt{10}

Perimeter = ST + TA + AR + RS

Perimeter = \sqrt{10} + \sqrt{10} + \sqrt{10} + \sqrt{10} = 4\sqrt{10}

4 0
4 years ago
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