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3 years ago

What are the zeros of fx) =-8x+ 16? Yes

Mathematics

2 answers:

timofeeve [1]3 years ago

5 0

Answer:

There is one Zero.

Step-by-step explanation:

Hope this helps:)

german3 years ago

5 0

The zeros are 2 but I am not sure

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Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0

Jlenok [28]

This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

4 0

3 years ago

Read 2 more answers

I need help Please and thank you What is the area of the triangle below? 21 yd 14 yd

lana [24]

Answer:

147 square yards

Step-by-step explanation:

Area = 21 x 14 x 1/2

Area = 294 x 1/2

Area = 147 yd ^ 2

Hope that helps! :)

-Aphrodite

3 0

3 years ago

Read 2 more answers

class A folds 160 fewer paper cranes than class B and 2/3 as many paper cranes as class C. Class B folds 92 more paper cranes th

krek1111 [17]

Let x = Class A
Let y = Class B
Let z = Class C
Equations from problem:
x - 160 = y
2/3x = z
y + 92 = z
Solving through substitution:
2/3x = y + 92
2/3x = (x - 160) + 92
2/3x = x - 68
-1/3x = -68
3(-1/3x) = 3(-68)
-x = -204
x = 204
Now substitute x in the first equation to get y:
204 - 160 = y
44 = y
44 = Class B
There are 44 folded paper cranes in Class B.

3 0

3 years ago

Pls help asap, I put attachments down below, I will also give brainliest

lesya [120]

Answer:

Question 1;

∴ The y values are 1.49 , 2.98 , 4.47 and 5.96

Question 2;

∴ The y values are 2.00 , 2.8 , 3.6 and 4.4

Question 3;

∴ The y values are -9 , -3 , 3 and 9

Question 4;

∴ y values are $\frac{1}{2}$ , $\frac{3}{4}$ , 1 and $\frac{5}{4}$

Step-by-step explanation:

Question 1;

Given data,

Apples cost $\$1.49$ per pound.

$x$ = weight in pound

$y$ = Cost in $\$$

Here the relation between $x$ and $y$ comes;

$y=x\times 1.49$ (equation 1)

Let, Plug all x value in equation 1;

when $x=1$ then $y=1\times 1.49=1.49$ ,

when $x=2$ then $y=2\times 1.49=2.98$ ,

when $x=3$ then $y=3\times 1.49=4.47$ ,

when $x=4$ then $y=4\times 1.49=5.96$ ,

∴ The y values are 1.49 , 2.98 , 4.47 and 5.96

Question 2;

From question,

Initial fees of cab is $\$$ 2.00 and Passengers are charged $\$$ 0.80 for every minute.

Let,

$x$ = Time in minutes

$y$ = Amount in $\$$

Here the relation between x and y comes;

$y=x\times 0.80 +2.00$ (equation 2)

Let,By plug all x value in equation 2;

When $x=0$ then $y=0\times 0.80+2.00=2.00$ ,

When $x=1$ then $y=1\times 0.80+2.00=2.8$ ,

When $x=2$ then $y=2\times 0.80+2.00=3.6$ ,

When $x=3$ then $y=3\times 0.80+2.00=4.4$ ,

∴ The y values are 2.00 , 2.8 , 3.6 and 4.4

Question 3;

Given relation between $x$ and $y$ ;

$y=6\times x +3$

Plug all the values of x in above equation,

When $x=-2$ then $y=(6\times -2) +3=-9$ ,

When $x=-1$ then $y=(6\times --1) +3=-3$ ,

When $x=0$ then $y=(6\times 0) +3=3$ ,

When $x=1$ then $y=(6\times 1) +3=9$ ,

∴ The y values are -9 , -3 , 3 and 9

Question 4;

Given relation between $x$ and $y$ ;

$y=(\frac{1}{4} \times x)+1$

Plug all the values of x in above equation,

When $x=-2$ then $y=(\frac{1}{4} \times -2)+1=\frac{1}{2}$ ,

When $x=-1$ then $y=(\frac{1}{4} \times -1)+1=\frac{3}{4}$ ,

When $x=0$ then $y=(\frac{1}{4} \times 0)+1=1$ ,

When $x=1$ then $y=(\frac{1}{4} \times 1)+1=\frac{5}{4}$ ,

∴ y values are $\frac{1}{2}$ , $\frac{3}{4}$ , 1 and $\frac{5}{4}$

7 0

4 years ago

Solve the following system of equations

Mila [183]

Answer:

y= 28/17

x= 57/17

Step-by-step explanation:

5x + 2y = 22

-2x + 6y = 3

(2)(5x + 2y = 22)→ 10x + 4y = 44

(5)(-2x + 6y = 3)→ -10x +30y = 15

Add this last eq → 34y=56 → y= 28/17

Replace this in any equation

-2x + 6(28/17) = 3 → x= - (54/17-168/17)/2 = 57/17

6 0

4 years ago