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2 years ago

Consider sample data with

Mathematics

1 answer:

postnew [5]2 years ago

4 0

The coefficient of variation is 20%

The lower limit is 9 and the upper limit is 21

<h3 /><h3>How to calculate the coefficient of variation</h3>

Given the following parameters

Sample mean "x" = 15
standard deviation 's" = 3

The coefficient of variation is expressed as:
coefficient of variation = s/x * 100

coefficient of variation = 3/15 * 100

coefficient of variation = = 20%

Hence the coefficient of variation is 20%

The formula for the Chebyshev interval is given as:

$(x- 3k, x + 3k)$

Get the value of k using the formula below:

$0.75=1-\frac{1}{k^2}\\ 0.25 = \frac{1}{k^2} \\k^2= \frac{1}{0.25} \\k = 2$

Get the required interval

$(15- 3(2), 15 + 3(2))\\(9,21)$

Hence the lower limit is 9 and the upper limit is 21

Learn more on confidence intervals here: brainly.com/question/15712887

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Henry and Blake are both runners. In 2 hours, Henry runs 14 miles. In 5 hours, Henry runs 35 miles. The graph below represents t

Tasya [4]

Henry runs at a rate of seven miles an hour. I think you meant the second sentence to be 'Blake', because there is not attatched graph. They are both running at the same speed in this case.

I got this because 14 (miles ran by Henry) / 2 (hours ran) you get 7. This same equation is applied to (Blake?) 35 (miles ran by [Blake?]) / 5 (hours ran) also equals seven.

If you meant the second statement to be Blake, they are both running at the same speed, and x=7.

If you didn't, then there is not enough information to determine Blake's speed.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)

3 0

3 years ago

two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the s

Korvikt [17]

Answer:

37.59 nautical miles

Explanation:

Distance = Speed x Time

The speed of the first ship = 12 knots

Thus, the distance covered after 1.5 hours

$\begin{gathered} =12\times1.5 \\ =18\text{ miles} \end{gathered}$

The speed of the second ship = 22 knots

Thus, the distance covered after 1.5 hours

$\begin{gathered} =22\times1.5 \\ =33\text{ miles} \end{gathered}$

The diagram representing the ship's path is drawn and attached below:

The angle at port = 90 degrees.

The triangle is a right triangle.

Using Pythagorean Theorem:

$\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}$

The two ships are 37.59 nautical miles apart after 1.5 hours.

8 0

1 year ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 50 feet cubed. A cylinder with height h a

Arada [10]

Answer:

Volume of the sphere is 66.67r/h

Step-by-step explanation:

Hello,

Volume of a sphere = ⁴/₃πr³

Volume of a cylinder = πr²h

The volume of the cylinder = 50ft³

But the cylinder and sphere both have the same radius and height

Volume of a cylinder = πr²h

50 = πr²h

Make r² the subject of formula

r² = 50/πh

Volume of a sphere = ⁴/₃πr³

Put r² into the volume of a sphere

Volume of a sphere = ⁴/₃π(50/πh)r

Volume of a sphere = ⁴/₃ × 50r/h

Volume of a sphere = ²⁰⁰/₃ r/h

Volume of a sphere = 66.67r/h

The volume of the sphere is 66.67r/h

7 0

4 years ago

1) (Modelo lineal de costo) Juan Chávez produce juguetes didácticos, para la fabricación de estos juguetes tiene costos fijos me

grandymaker [24]

Answer:

C = 2000 + 25 * X

$ 7000

Step-by-step explanation:

We have that the value of the total costs is equal to the fixed costs plus the variable costs.

As fixed costs we have $ 2000 and variable cost we have $ 25 for each unit, that is, the equation for total costs would be:

Let x be the number of toys, then:

C = 2000 + 25 * X

If there are 200 toys, the cost would be:

Replace x with 200:

C = 2000 + 25 * 200

C = 7000

In other words, the cost of producing 200 toys would be $ 7000.

7 0

4 years ago

Use quadrilateral ABCD to find the value of x. The figure is not drawn to scale. Use the following dimensions: m⦨ABC = 4x◦, m⦨BC

OLEGan [10]

Answer/Step-by-step explanation:

Question 1:

Interior angles of quadrilateral ABCD are given as: m<ABC = 4x, m<BCD = 3x, m<CDA = 2x, m<DAB = 3x.

Since sum of the interior angles = (n - 2)180, therefore:

$4x + 3x + 2x + 3x = (n - 2)180$

n = 4, i.e. number of sides/interior angles.

Equation for finding x would be:

$4x + 3x + 2x + 3x = (4 - 2)180$

$12x = (2)180$

$12x = 360$

$x = \frac{360}{12}$ (dividing each side by 12)

$x = 30$

Find the measures of the 4 interior angles by substituting the value of x = 30:

m<ABC = 4x

m<ABC = 4*30 = 120°

m<BCD = 3x

m<BCD = 3*30 = 90°

m<CDA = 2x

m<CDA = 2*30 = 60°

m<DAB = 3x

m<DAB = 3*30 = 90°

Question 2:

<CDA and <ADE are supplementary (angles on a straight line).

The sum of m<CDA and m<ADE equal 180°. To find m<ADE, subtract m<CDA from 180°.

m<ADE = 180° - m<CDA

m<ADE = 180° - 60° = 120°

6 0

3 years ago