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cupoosta [38]
3 years ago
6

when the day began it was 23 f mid day it went up 15 and then dropped 19 by midnight what was the temperature at midnight?

Mathematics
1 answer:
xeze [42]3 years ago
5 0
The tempurature at midnight was 19 degrees Fahrenheit.
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The shed is filled with sawdust whose density (kg/m3) at any point is proportional to the distance of that point from the floor.
postnew [5]
It is important to note that when we say proportional, the increase in the value of the independent variable (in this case, distance x) will also increase the value of the dependent variable (density, d). Using k as the proportionality constant, the answer to this question would then be,
                                        d = kx
3 0
3 years ago
Factor 28 + 56t + 28w to identify the equivalent expressions. Choose 2 answers
ra1l [238]

Answer:

28+56t+28w=14(2+4t+2w)\\\\28+56t+28w=28(1+2t+w)

Step-by-step explanation:

28+56t+28w=14\times 2+14\times 4t+14\times 2w\\\\14\ is\ common\ in\ every\ term\\\\28+56t+28w=14(2+4t+2w).........................................(1)\\\\Now\ take\ 2+4t+2w\\\\2+4t+2w=2+2\times 2t+2w\\\\2\ is\ common\\\\2+4t+2w=2(1+2t+1)\\\\Now\ substitute\ this\ in\ equation\ 1\\\\28+56t+28w=14\times 2(1+2t+w)\\\\28+56t+28w==28(1+2t+w)

3 0
4 years ago
Read 2 more answers
What is the meaning of the slope of the line ?
Mila [183]

Step-by-step explanation: In algebra, we use the word <em>slope</em> to describe how steep a line is and slope can be found using the ratio <em>rise/run </em>between any two points that are on that line.

The ratio <em>rise/run</em> is the equal to the rate of change

or the <em>change in y/change in x</em>.

In algebra, the rate of change or the <em>change in y/change in x</em> or

the <em>rise/run</em> is also called the slope of a line.

4 0
3 years ago
Please help quickly thanks :)
marusya05 [52]

(0, 0) → t = 0, w = 0 → w = 0 · 0

(1, 4) → t = 1, w = 4 → w = 1 · 4

(2, 8) → t = 2, w = 8 → w = 2 · 4

(3, 12) → t = 3, w = 12 → w = 3 · 4

<h3>Answer: w = 4t</h3>
8 0
3 years ago
How do I find this help please
KIM [24]
Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center  ( in radians)

In this case m < theta = 360 - 235 = 125 degrees or  2.182 radians

So, the area of shaded area = 1/2 * 20^2 * 2.182 =   436.4 in^2
8 0
4 years ago
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