check the picture below.
so the triangular prism is really just 3 rectangles and 2 right-triangles,
now, we know the base of one of the triangles is 2.6, what's its height?
since it's a right-triangle, we can simply use the pythagorean theorem to get "h".
so, we can now, simply get the area of both of the triangles and the three rectangles and sum them up, and that's the area of the triangular prism.
![\bf \stackrel{two~triangles}{2\left[ \cfrac{1}{2}(2.6)(4.5) \right]}~~+~~\stackrel{rectangle}{(2.6\cdot 4.3)}~~+~~\stackrel{rectangle}{(4.3\cdot 3.9)}~~+~~\stackrel{rectangle}{(4.3\cdot 5.2)} \\\\\\ 11.7+11.18+22.36\implies \blacktriangleright 45.24 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Btwo~triangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.6%29%284.5%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%282.6%5Ccdot%204.3%29%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%284.3%5Ccdot%203.9%29%7D~~%2B~~%5Cstackrel%7Brectangle%7D%7B%284.3%5Ccdot%205.2%29%7D%0A%5C%5C%5C%5C%5C%5C%0A11.7%2B11.18%2B22.36%5Cimplies%20%5Cblacktriangleright%2045.24%20%5Cblacktriangleleft)
The times plus method.... is where a mixed number.... for example, to get the improper fraction of 3 1/4, you multiply 4 and three, and add that number with 1. (try writing it on a piece of paper, times between the whole number and denominator, and a plus between the whole number and the numerator.) anyway we are going to use the reverse for this.
SO the numerator is 17, and 17 is divisible by 5..... 3 times (u get where I'm going??) and there's 2 left over so...... the answer for that one should be 3 2/5
Since 3 x 5= 15+2 is 17 ;)))
Moving ON for the one....pick like 15 or 16 to be the denominator.... and subtract the 15 or 16 from 17, and the number you get is your numerator...
Matilda only ate 1/12 of the pie as 1/2 of 1/6 = 1/12
I believe its -1 because x2-x1/y2-y1 good luck
Answer:
6.8%
Step-by-step explanation:
the question has no information about class size (no. of student in class)
assume no. of student is infinite
P(3brown out of 6) = 6C3 * P(brown)^3 * P(not brown)^3
= 20 * 0.004913 * 0.695789
= 0.06837
