Answer: Exactly square root 58 inches
Step-by-step explanation: The dimensions given for the right angled triangle are 7 inches and 3 inches respectively. The third side is yet unknown. However what we know is that a right angled triangle can be solved by using the Pythagoras theorem which states that,
AC^2 = AB^2 + BC^2
Where AC is the longest side. The question requires us to calculate the longest side and with the other two sides already known, the Pythagoras theorem now becomes,
AC^2 = 7^2 + 3^2
AC^2 = 49 + 9
AC^2 = 58
Add the square root sign to both sides of the equation
AC = square root 58 inches
Answer: A, n=o+3
Step-by-step explanation:
Nathan (n) is 3 years older than Olivia (o) so Nathan's age would equal Olivia's age plus 3 years.
Hope this helps :)
The complete sentence for the <em>unit</em> circle is:
<em>When t = 0, AP = 0, so sin t will begin at a value of 0. As t increases from 0 to π/2, sin t increases. Eventually, when t = π/2, OP will be 0, so sin t = AP will be 1.</em>
<h3>How to complete a sentence with concepts from trigonometry</h3>
In this problem we have sentence to be completed by direct observation to the variables seen in a unit circle, a form used to teach trigonometric functions in a <em>graphic</em> manner. Now we proceed to present the complete sentence below:
<em>When t = 0, AP = 0, so sin t will begin at a value of 0. As t increases from 0 to π/2, sin t increases. Eventually, when t = π/2, OP will be 0, so sin t = AP will be 1.</em>
To learn more on trigonometric functions: brainly.com/question/6904750
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Answer:
y=x, x-axis, y=x, y-axis
Explanation:
Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.
Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.
However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.
