2 years ago

For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?

Mathematics

1 answer:

adelina 88 [10]2 years ago

4 0

Answer:

(2 + 1)^2 + 2 = 10 - 6

Falso

Step-by-step explanation:

The left side

does not equal to the right side

, which means that the given statement is false.

False

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Rationalize the denominator of \frac{1 \sqrt{3}}{1-\sqrt{3}}. When you write your answer in the form A B\sqrt{C}, where A, B, an

kobusy [5.1K]

Answer:

The value of ABC is 6.

Step-by-step explanation:

Consider the expression

$\frac{1+\sqrt{3}}{1-\sqrt{3}}$

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$\frac{1+\sqrt{3}}{1-\sqrt{3}}\times \frac{1+\sqrt{3}}{1+\sqrt{3}}$

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$\frac{4+2\sqrt{3}}{-2}$

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The answer in the form

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3 years ago

Please help me with this

KIM [24]

Answer:

0.40

Step-by-step explanation:

Sin(T) is Opposite over Hypotenuse, which is RS/ST.

ST = sqrt(43) so we can plug that in.

To find RS, use the Pythagorean theorem, so, 6^2+ (RS)^2= 43.

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Thus, Sin(T) = sqrt(7/43) or 0.40

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2 years ago