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rjkz [21]
3 years ago
6

Blood groups o a and b

Chemistry
1 answer:
Kaylis [27]3 years ago
5 0
Oh ah oh ah cheer up baby
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Is a group of deer in a field called a community or a population?
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3 years ago
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Nickel has an FCC structure and an atomic radius of 0.124 nm. (12 points) a. What is the coordination number? b. Calculate the A
LekaFEV [45]

Answer:

a)CN=12

b)APF=74 %

c)a=0.35 nm

d)ρ=9090.9 Kg/m^3

Explanation:

Given that

Nickel have FCC structure

We know that in FCC structure ,in FCC 8 atoms at corner with 1/8 th part in one unit cell and 6 atoms at faces with 1/2 part in one unit cell .

Z=8 x 1/8 + 1/2 x 6 =4

Z=4

Coordination number (CN)

 The number of atoms which touch the second atoms is known as coordination number.In other word the number of nearest atoms.

CN=12

Coordination number of FCC structure is 12.These 12 atoms are 4 atoms at the at corner ,4 atoms at 4 faces and 4 atoms of next unit cell.

APF

APF=\dfrac{Z\times \dfrac{4}{3}\pi R^3}{a^3}

We know that for FCC

4R=\sqrt{2}\ a

Now by putting the values

APF=\dfrac{4\times \dfrac{4}{3}\pi R^3}{\left(\dfrac{4R}{\sqrt2}\right)^3}

APF=0.74

APF=74 %

4R=\sqrt{2}\ a

4\times 0.124=\sqrt{2}\ a

a=0.35 nm

Density

\rho=\dfrac{Z\times M}{N_A\times a^3}

We know that M for Ni

M=58.69 g/mol

a=0.35 nm

N_A=6.023\times 10^{23}\ atom/mol

\rho=\dfrac{Z\times M}{N_A\times a^3}

\rho=\dfrac{4\times 58.69}{6.023\times 10^{23}\times( 0.35\times 10^{-9})^3}\ g/m^3

ρ=9090.9 Kg/m^3

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3 years ago
Write net ionic equation to show the reaction of aqueous hg2(no3)2 with aqueous sodium chloride to form solid hg2cl2 and aqueous
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The net ionic equations in the creation of solid Hg2Cl2 and aqueous Sodium Nitrate (NaNO3) would be:

Hg2(NO3)2 + 2 NaCl --------> Hg2Cl2 + 2 NaNO3 <span>
Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl2 + 2Na+ + 2NO3-1 
<span>Hg2+2 + 2Cl-1 ------------> Hg2Cl2</span></span>

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4 years ago
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A catalyst increases the reaction rate of a reaction by (3 points)
Minchanka [31]

Answer:

A catalyst increases the rate of reaction by decreasing activation energy. ... Enzymes are highly substrate specific and catalyze reactions by providing an alternate pathway of lower activation energy.

Explanation:

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C5H9O+O2=CO2+H2O balance equation
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2 C5H12O + 15 O2 = 10 CO2 + 12 H2O

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