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2 years ago

MATCH EACH PLease quick

Mathematics

2 answers:

seraphim [82]2 years ago

3 0

Answer:

The green one go to the 5th one and the orange go to the 1st one and the red go to the 4th one and the purple go to the 3rd and the green go to the 2nd one

Step-by-step explanation:

Have a great day hope its right

Olin [163]2 years ago

3 0

Answer:

2 = 4

1 = 5

3 = 2

5 = 3

4 = 1

Step-by-step explanation:

Hope it's right sorry if it's wrong

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Answer:

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Step-by-step explanation:

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3 years ago

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AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

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$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

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