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3 years ago

5

What is the smallest number that has a remainder of 1, 2, and 3 when divided by 2, 3, and 4, respectively? Are there more number

s that have this property?

2 answers:

atroni [7]3 years ago

5 0

<u>11</u> and <u>2</u><u>3</u> are the answers.

Step-by-step explanation:

Multiple of 2 increase 1 =

$3,5,7,9,11,13,15,17...$

Multiple of 3 increase 2 =

$5,8,11,14,17...$

Multiple of 4 increase 3 =

$7,11,15,19...$

Here, we can see the smallest number is <u>1</u><u>1</u>

There are more numbers having this property such as 23.

$23 \div 2 = 11...1$

$23 \div 3 = 7...2$

$23 \div 4 = 5...3$

Kitty [74]3 years ago

4 0

Answer:

11 is the answer.

Step-by-step explanation:

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