Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Answer:
x = √6/2
Step-by-step explanation:
Side a = 1.73205 --> √3
Side b = 1.22474 --> √6/2
Side c = 1.22474 --> √6/2
Use the equation
For A. The problem would be set up like so
5 _ -1
--------
4 _ -2
Start by subtracting 5 minus -1 which is 6 because minus a negative becomes a positive then subtract 4 minus -2 which is 6, remember minus a negative becomes a positive, then divide 6/6 to get 1
For B.
-5 _ -0
----------
3 _ -1
Again subtract -5 by -0 which no matter what will be -5. Then make -1 positive because it's a subtracted negative so it becomes 3+1 which gives you 4. Your answer is -5/4
If you need help with the rest message me good luck
The answer is 125. Just for you to understand all you have to do is 20 *____ =625 in this case 20*125=625 :)