Math problem, please help:)

1)Circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1)(2, 1) and has a radiu

galina1969 [7]

Figures of same shape and size are similar .Two circles C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = $\pi.r^{2}\alpha$ ÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

8 0

3 years ago

Plz solve I’ve been stuck on how to start it and I just can’t

AleksAgata [21]

Answer:

x and y = 0

the question looks weird and almost wrong because when you subtract the equations, you are left with nothing

Step-by-step explanation:

Multiply the top equation by 3 to make the -x a -3x instead.

Then do the top equation - the bottom equation

At this point you should be left with x

7 0

3 years ago

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HELP ME HELP<br><br>PLZ<br><br>PLZ<br><br>PLZ

lorasvet [3.4K]

Answer: 3, 2, 1, 0, -1

Step-by-step explanation:

3, 2, 1, 0, -1

7 0

3 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

2 years ago

Darcy and Leah are looking at some fabric selections in a store. All of the selections are marked the same price, and the amount

alex41 [277]

We know that the price of all the fabrics is the same. However, the length of the fabrics is different. We have to determine which fabric is the longest.

Option A: $\frac{43}{5}$ = 8.6

Option B: $\frac{33}{4}$ = 8.25

Option C: $\frac{78}{9}$ = 8.6667

Option D: $\frac{22}{3}$ = 7.33....

Hence, the longest fabric is the one given in option C, and its length is 8.6667

5 0

3 years ago

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