3 years ago

Pls help hella lost

1 answer:

4 0

L = -4,4
E = -2, -3
N = 2,1
I = 4,3
E = 1,3

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valkas [14]

Line a has a larger value

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4 years ago

Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

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2 years ago

Vadim26 [7]

Answer:

Step-by-step explanation:

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3 years ago

konstantin123 [22]

All 3 equations the Answer is v= 13/2

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3 years ago

masya89 [10]

Answer:it would be exactly to the other side of y

Step-by-step explanation:

like say -2,1 would reflect as 2,1

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3 years ago