Answer:
send the graph and ill solve it
Step-by-step explanation:
Answer:
Step-by-step explanation:
Since we are to show by Pythagoras that the square will fit inside the circle without touching the edge of the circle , this means that we must find the value of the length of the diagonal of the square using Pythagoras.
For the square to fit in without touching the edge of the circle , this means that the diagonal of the square must be less than the diameter of the circle.
Length of the square is 5cm.
Recall Pythagoras theorem: it states that
the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides
=
+
= 25 + 25
= 50
Take the square root of both sides , that is
D = 
D =
X
, since 50 = 25 x 2
D = 5
D ≈ 7.07
Note that the diameter of the circle given is 9 and D < 9 , we can therefore conclude that the square will fit inside the circle without touching the edge of the circle since the diagonal of the square is less than the diameter of the circle
Answer:
300
Step-by-step explanation:
Since it says first rounding both numbers to the tenth place you will round 12 and 27
12 = 10
27 = 30
10 times 30 = 300
Hope this helps dude
360 is the answer that your looking for