1) As you move from left to right on the electromagnetic spectrum, What happens to frequency? QUIIICK HELPPPPP!!!!!!

What is the orbital period in years of a planet with a semi major axis of 35 au

mezya [45]

Answer:

Orbital period of the planet will be 207.06 year

Explanation:

We have given the planet have the semi major axis as 35 au

We have to find the orbital period of the planet

From Keplar's third law there is relation between the orbital period and semi major axis which is t $T^2=R^3$

So $T^2=35^3$

$T^2=42875$

$T=207.06year$

So orbital period of the planet will be 207.06 year

6 0

4 years ago

The radius of the aorta is «10 mm and the blood flowing through it has a speed of about 300 mm/s. A capillary has a radius of ab

stealth61 [152]

Answer:

(I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is $3.74\times10^{9}$

Explanation:

Given that,

Radius of aorta = 10 mm

Speed = 300 mm/s

Radius of capillary $r=4\times10^{-3}\ mm$

Speed of blood $v=5\times10^{-4}\ m/s$

(I). We need to calculate the effective cross sectional area of the capillaries

Using continuity equation

$A_{1}v_{1}=A_{2}v_{2}$

Where. v₁ = speed of blood in capillarity

A₂ = area of cross section of aorta

v₂ =speed of blood in aorta

Put the value into the formula

$A_{1}=A_{2}\times\dfrac{v_{2}}{v_{1}}$

$A_{1}=\pi\times(10\times10^{-3})^2\times\dfrac{300\times10^{-3}}{5\times10^{-4}}$

$A_{1}=0.188\ m^2$

(II). We need to calculate the approximate number of capillaries

Using formula of area of cross section

$A_{1}=N\pi r_{c}^2$

$N=\dfrac{A_{1}}{\pi\times r_{c}^2}$

Put the value into the formula

$N=\dfrac{0.188}{\pi\times(4\times10^{-6})^2}$

$N=3.74\times10^{9}$

Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².

(II). The approximate number of capillaries is $3.74\times10^{9}$

3 0

3 years ago

A traffic-safety engineer is designing a deceleration lane. She is basing the length of

Mice21 [21]

The deceleration of the car is observed as 2 m/s^2.

<h3>What is deceleration?</h3>

The term deceleration has to do with the decrease of velocity with time.

Given that;

v = 65 km/h or 18 m/s

u = 126 km/h to or 35 m/s

t = 8.5 s

a = ?

v = u - at

18 - 35 = -8.5a

a = 18 - 35/-8.5

a = 2 m/s^2

Learn ore about deceleration:brainly.com/question/4403243?

#SPJ1

7 0

3 years ago

A meteor is approaching Earth. Which statement about its motion is true?

ankoles [38]

the answer is b trust me its b

8 0

3 years ago

Help me please (*￣(ｴ)￣*)

Len [333]

Answer:

1) Are always conservative

Explanation:

Elastic forces are always conservative.

Hope it helps you.

please mark as the brainliest answer.

3 0

3 years ago

Read 2 more answers