1 watt = 1 joule per second = 1 newton meter per second = 1 kg m2 s-3
Answer:
0.4 g/cm^3
Explanation:
The density of an object can be found using the following formula.
d= m/v
where m is the mass and v is the volume.
The mass of the metal is 6 grams and the volume is 15 centimeters^3
m=6 g
v= 15 cm^3
Substitute these into the formula.
d= 6 g/ 15 cm^3
Divide 6 g by 15 cm^3 (6/15=0.4)
d= 0.4 g/ cm^3
The density of the metal is 0.4 grams per cubic centimeter.
Answer:
Explanation:
Let that point be at a distance x from q1
Then Kq1/x^2= Kq2/ (s-x)^2
Taking square roots and simplifying, x =s /[1+(q2/q1)^0.5]
Assuming an identical distance, the rigidity of Q on 2Q is equivalent in value to the rigidity of 2Q on Q. for that reason, had the area R been stored an identical, the two forces could be equivalent. inspite of the shown fact that, via fact the area is being decreased, we could constantly consult with the equation we use to calculate those forces: F = ok(Q1xQ2)/(R^2) because R is squared and is being halved, the final result's that's it being divided by potential of a million/4. for that reason, the rigidity would be expanded by potential of four, and be 4F.
Answer:
v = 666.667 m/s
Explanation:
<u>Given</u>: length L = 25 cm = 0.25 m, B = 600 G = 0.06 T ( 1G = 0.0001 T)
emf= 10 V
Solution:
emf = vBL
v= emf / BL
v = 10 V / (0.06 T× 0.25 m)
v = 666.667 m/s
