Answer:
9656.06 meters because youd go 6 miles and 9656.06 is 6 miles but just in meters. I hope this helps :)
Explanation:
<span>The wires are suspended diagonally, meaning the tension in each is directed diagonally as well (along the wire). We can, however, talk about the horizontal and vertical components of the tension force. The horizontal tension force in each wire is Tcosθ, while the vertical tension force is Tsinθ.
The horizontal tension forces balance one another, because the wires are pulling in opposite directions. This means Tcosθ=Tcosθ, which is obvious but not very helpful. If you look at the vertical tension forces on the other hand, you can see that they must balance the weight of the body for the system to be in equilibrium. In other words:
Tsinθ+Tsinθ=mg
You're given enough information in the question to solve for T using this equation!</span>
Answer:
F = 789 Newton
Explanation:
Given that,
Speed of the car, v = 10 m/s
Radius of circular path, r = 30 m
Mass of the passenger, m = 60 kg
To find :
The normal force exerted by the seat of the car when the it is at the bottom of the depression.
Solution,
Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.
N = 788.6 Newton
N = 789 Newton
So, the normal force exerted by the seat of the car is 789 Newton.
By definition we have to:
LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
Where,
k1 = 0.0117 s-1
K2 = 0.689 s-1
T1 = 400.0 k
T2 = 450.0 k
R is the ideal gas constant
R = 8.314 KJ / (Kmol * K)
Substituting
ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
Clearing Ea:
Ea = 122 kJ
answer
<span> the activation energy in kilojoules for this reaction is
</span> Ea = 122 kJ
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