Answer:
(I). The effective cross sectional area of the capillaries is 0.188 m².
(II). The approximate number of capillaries is ![3.74\times10^{9}](https://tex.z-dn.net/?f=3.74%5Ctimes10%5E%7B9%7D)
Explanation:
Given that,
Radius of aorta = 10 mm
Speed = 300 mm/s
Radius of capillary ![r=4\times10^{-3}\ mm](https://tex.z-dn.net/?f=r%3D4%5Ctimes10%5E%7B-3%7D%5C%20mm)
Speed of blood ![v=5\times10^{-4}\ m/s](https://tex.z-dn.net/?f=v%3D5%5Ctimes10%5E%7B-4%7D%5C%20m%2Fs)
(I). We need to calculate the effective cross sectional area of the capillaries
Using continuity equation
![A_{1}v_{1}=A_{2}v_{2}](https://tex.z-dn.net/?f=A_%7B1%7Dv_%7B1%7D%3DA_%7B2%7Dv_%7B2%7D)
Where. v₁ = speed of blood in capillarity
A₂ = area of cross section of aorta
v₂ =speed of blood in aorta
Put the value into the formula
![A_{1}=A_{2}\times\dfrac{v_{2}}{v_{1}}](https://tex.z-dn.net/?f=A_%7B1%7D%3DA_%7B2%7D%5Ctimes%5Cdfrac%7Bv_%7B2%7D%7D%7Bv_%7B1%7D%7D)
![A_{1}=\pi\times(10\times10^{-3})^2\times\dfrac{300\times10^{-3}}{5\times10^{-4}}](https://tex.z-dn.net/?f=A_%7B1%7D%3D%5Cpi%5Ctimes%2810%5Ctimes10%5E%7B-3%7D%29%5E2%5Ctimes%5Cdfrac%7B300%5Ctimes10%5E%7B-3%7D%7D%7B5%5Ctimes10%5E%7B-4%7D%7D)
![A_{1}=0.188\ m^2](https://tex.z-dn.net/?f=A_%7B1%7D%3D0.188%5C%20m%5E2)
(II). We need to calculate the approximate number of capillaries
Using formula of area of cross section
![A_{1}=N\pi r_{c}^2](https://tex.z-dn.net/?f=A_%7B1%7D%3DN%5Cpi%20r_%7Bc%7D%5E2)
![N=\dfrac{A_{1}}{\pi\times r_{c}^2}](https://tex.z-dn.net/?f=N%3D%5Cdfrac%7BA_%7B1%7D%7D%7B%5Cpi%5Ctimes%20r_%7Bc%7D%5E2%7D)
Put the value into the formula
![N=\dfrac{0.188}{\pi\times(4\times10^{-6})^2}](https://tex.z-dn.net/?f=N%3D%5Cdfrac%7B0.188%7D%7B%5Cpi%5Ctimes%284%5Ctimes10%5E%7B-6%7D%29%5E2%7D)
![N=3.74\times10^{9}](https://tex.z-dn.net/?f=N%3D3.74%5Ctimes10%5E%7B9%7D)
Hence, (I). The effective cross sectional area of the capillaries is 0.188 m².
(II). The approximate number of capillaries is ![3.74\times10^{9}](https://tex.z-dn.net/?f=3.74%5Ctimes10%5E%7B9%7D)